答案 0 :(得分:6)
使用linear-gradient
背景图片创建非常简单,我们不需要多个div
元素来创建渐变。我们只需要一些渐变图像。
下面解释了如何实现形状:
注意:相关图片中的第三个条似乎比其他条稍低,我假设这是图像中的错误。如果不是,仍然可以通过以下方法实现。
body {
background: yellow;
}
.shape {
height: 100px;
width: 400px;
transform: skew(-30deg);
transform-origin: left bottom;
background-image: linear-gradient(to left, rgba(255,255,255,0.5) 25%, transparent 25%, transparent 33%, rgba(255,255,255,0.75) 33%, rgba(255,255,255,0.5) 60%, transparent 60%, transparent 66%, rgba(255,255,255,1) 66%, rgba(255,255,255,0.75) 93%, transparent 93%), linear-gradient(white, white);
background-size: 15% 100%, 85% 75%;
background-position: 100% 100%, 0% 0%;
background-repeat: no-repeat;
}

<div class='shape'></div>
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您还可以使用SVG path
元素来创建此形状。
.shape {
position: relative;
height: 100px;
width: 300px;
}
.shape svg {
position: absolute;
height: 100%;
width: 100%;
top: 0px;
left: 0px;
}
.shape svg path#white-bar {
fill: rgba(255, 255, 255, 1);
}
.shape svg path#translucent-bar-1 {
fill: rgba(255, 255, 255, 0.75);
}
.shape svg path#translucent-bar-2 {
fill: rgba(255, 255, 255, 0.5);
}
body {
background: yellow;
}
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<div class='shape'>
<svg viewBox='0 0 300 100'>
<path d='M0,75 25,0 240,0, 221.5,75z M245,0 220,100 235,100 260,0' id='white-bar' />
<path d='M265,0 240,100 255,100 280,0' id='translucent-bar-1' />
<path d='M285,0 260,100 275,100 300,0' id='translucent-bar-2' />
</svg>
</div>
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注意:很可能使用单个path
元素和有角度的渐变填充来创建它,但我对SVG不太好。
答案 1 :(得分:2)
答案 2 :(得分:1)
调整@Siddarth的代码,这可能更适合上面给出的图像:
div{
display:inline-block;
vertical-align: text-top;
-webkit-transform: skew(-20deg);
-moz-transform: skew(-20deg);
-o-transform: skew(-20deg);
background: white;
}
.one{
width: 450px;
height: 100px;
}
div:not(.one){
margin-left:0px;
width: 20px;
height: 200px;
}
.two{
opacity:.8;
}
.three{
opacity:.6;
}
.four{
opacity:.4;
}
body {
background-color: rgb(255, 210, 2);
}
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<body>
<div class="one">
</div>
<div class="two">
</div>
<div class="three">
</div>
<div class="four">
</div>
</body>
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