无法在Swift 2中将type（）的值转换为闭包结果类型NSDictionary

Question

我必须返回此函数的值。我在此行中收到错误

func GetStation(url : String, completionHandler: (stationDictionary: NSDictionary) -> ()) {

    getResonse(url, completionhandler: { (dict) -> NSDictionary in
       completionHandler(stationDictionary: dict) // Error on this line 
    })

}

Answer 1

这肯定有效。

func GetStation(url : String, completionHandler: (stationDictionary: NSDictionary) -> NSDictionary) {

    getResonse(url, completionhandler: { (dict) -> NSDictionary in
       completionHandler(stationDictionary: dict) // Error on this line 
    })
}

并使用它，

var dict = NSDictionary()
temp.GetStation("your url") { (stationDictionary) -> NSDictionary in
            dict = stationDictionary;
            print("your dictionary := \(stationDictionary)")
        }

Answer 2

    let myStr = "POINT(101.650577657408 3.1653186153213)"
    let strWithout_POINT_openingBrace = myStr.stringByReplacingOccurrencesOfString("POINT(", withString: "")//"101.650577657408 3.1653186153213)"
    let strWithout_closingBrace = strWithout_POINT_openingBrace.stringByReplacingOccurrencesOfString(")", withString: "")//"101.650577657408 3.1653186153213"
    //now you have only space between two values
    //so split string by space
    let arrStringValues = strWithout_closingBrace.componentsSeparatedByString(" ");//["101.650577657408","3.1653186153213"]

    print(arrStringValues[0]);//first value "101.650577657408"
    print(arrStringValues[1]);//second value "3.1653186153213"

Answer 3

你可能错误的getResonse代码...... 它应该像下面..

  func getResonse(url : String, completionHandler: (dictionary:NSDictionary) -> Void) {
  }

所以你应该像下面的那样打电话给GetStation ......

  func GetStation(url : String, completionHandler: (stationDictionary: NSDictionary) -> NSDictionary) {

  getResonse(url) { (dictionary) -> Void in
        return completionHandler(stationDictionary: dictionary)
    }
 }