我有一些<selects>
我需要填充一些取决于当前登录用户的choices
。我不认为这可以(或很容易)从表单类中进行,所以我可以将选项留空并在视图中设置它们吗?或者我应该采取什么方法?
答案 0 :(得分:5)
不确定这是否是最好的答案,但过去我已经在表单的 init 中设置了选择字段的选项 - 您可能会将您的选择传递给您的构造函数形式...
答案 1 :(得分:2)
您可以在视图中动态构建表单(实际上,我宁愿将代码保留在视图之外的自己的函数中,只是在视图中调用它,但这只是详细信息)
我在一个项目中这样做了:
user_choices = [(1, 'something'), (2, 'something_else')]
fields['choice'] = forms.ChoiceField(
choices=user_choices,
widget=forms.RadioSelect,
)
MyForm = type('SelectableForm', (forms.BaseForm,), { 'base_fields': fields })
form = MyForm()
显然,您需要根据当前用户创建user_choices
并添加您需要的任何字段以及选项,但这是一个基本原则,我将其余部分作为读者练习。< / p>
答案 2 :(得分:1)
考虑到您已将用户作为参数包含在内,我将使用自定义标记解决此问题。
在你的app / templatetags / custom_tags.py中这样:
@register.simple_tag
def combo(user, another_param):
objects = get_objects(user, another_param)
str = '<select name="example" id="id_example">'
for object in objects:
str += '<option value="%s">%s</option>' % (object.id, object.name)
str += '</select>'
return mark_safe(str)
然后在你的模板中:
{% load custom_tags %}
{% special_select user another_param %}
有关自定义标记的更多信息http://docs.djangoproject.com/en/dev/howto/custom-template-tags/
答案 3 :(得分:0)
<强> Forms.py 强>
class MyForm(forms.Form):
""" Initialize form values from views"""
select=forms.BooleanField(label='',required=False)
field_1=forms.CharField(label='',widget=forms.TextInput(attrs= \
{'size':'20','readonly':'readonly',}))
field_2=forms.ChoiceField(widget=forms.Select(), \
choices=((test.id,test.value) for test in test.objects.all()))
def __init__(self, *args, **kwargs):
super(MyForm, self).__init__(*args, **kwargs)
input=kwargs.get('initial',{})
get_field_1_initial_input_from_views=re.sub("\[|\]|u'|'","",str (input.values()))
# override field_2 choices based on field_1 input
try:
# filter choices
self.fields[‘field_2'].choices=((test.id,test.value) for test in test.objects.filter ( --------)))
except:
pass
<强> Views.py 强>
def views_function(request,val):
"""Dynamically generate input data for formset."""
Initial_data=[]
initial_data.append({'field_1':data.info})
#Initializing formset
MyFormSet=formset_factory(MyForm,extra=0)
formset=MyFormSet(initial=initial_data)
context={'formset':formset}
if request.method == 'POST':
formset=MyFormSet(request.POST,request.FILES)
if formset.is_valid():
# You can work with the formset dictionary elements in the views function (or) pass it to
#Forms.py script through an instance of MyForm
return HttpResponse(formset.cleaned_data)
return render_to_response(‘test.html', context,context_instance=RequestContext(request))