用于连接网址
postgres://swnstvngfhgcks:s6oqSe93DVkrcEnyJEHStzpfAt@ec2-54-235-170-124.compute-1.amazonaws.com:5432/d3tqm9uep7oufb
我使用以下persistence
设置
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="HotelPU" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQL82Dialect"/>
<property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver"/>
<property name="javax.persistence.jdbc.url" value="postgres://ec2-54-235-170-124.compute-1.amazonaws.com:5432/d3tqm9uep7oufb"/>
<property name="javax.persistence.jdbc.user" value="swnstvngfhgcks"/>
<property name="javax.persistence.jdbc.password" value="s6oqSe93DVkrcEnyJEHStzpfAt"/>
<property name="javax.persistence.schema-generation.database.action" value="create"/>
<property name="javax.persistence.schema-generation.create-source" value="script"/>
<property name="javax.persistence.schema-generation.create-script-source"
value="sql/hotel_postgres.sql"/>
</properties>
</persistence-unit>
</persistence>
但我得到以下例外:
Caused by: org.hibernate.HibernateException: Unable to make JDBC Connection [postgres://ec2-54-235-170-124.compute-1.amazonaws.com:5432/d3tqm9uep7oufb]
at org.hibernate.engine.jdbc.connections.internal.BasicConnectionCreator.createConnection(BasicConnectionCreator.java:77)
at org.hibernate.engine.jdbc.connections.internal.DriverManagerConnectionProviderImpl.configure(DriverManagerConnectionProviderImpl.java:106)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:111)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:234)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:206)
at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.buildJdbcConnectionAccess(JdbcServicesImpl.java:260)
at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.configure(JdbcServicesImpl.java:94)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:111)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:234)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:206)
at org.hibernate.cfg.Configuration.buildTypeRegistrations(Configuration.java:1885)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1843)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:850)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:843)
at org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:398)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:842)
at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:75)
我错在哪里
答案 0 :(得分:3)
将javax.persistence.jdbc.url属性更改为jdbc:postgresql:
前缀,而不只是postgres:
jdbc:postgresql://ec2-54-235-170-124.compute-1.amazonaws.com:5432/d3tqm9uep7oufb
的文档