Question

我正在使用select2和ajax在我的数据库中查询特定分类下的条款，但是当我搜索搜索框时，只是挂起＆＃34;搜索＆＃34;没有检索任何结果。

这是我的HTML

<select multiple="" name="regions1[]" id="regions1" class="job-manager-multiselect select2-hidden-accessible" required="" tabindex="-1" aria-hidden="true"></select>

我的jquery：

<script>
jQuery(function($) {
$(document).ready(function() {
$( "#regions1" ).select2({        
ajax: {
    url: "/ajax/connect.php",
    dataType: 'json',
    delay: 250,
    data: function (params) {
        return {
            q: params.term // search term
        };
    },
    processResults: function (data) {
        // parse the results into the format expected by Select2.
        // since we are using custom formatting functions we do not need to
        // alter the remote JSON data
        return {
            results: data
        };
    },
    cache: true
},
minimumInputLength: 2
  });
  });
   });
 </script>

和我的php代码来查询数据库，我希望获得分类标准下的所有术语名称＆＃34; job_listing_region＆＃34;

<?php

  $servername = "localhost";
  $username = "myusername";
  $password = "mypassword";

   try {
$conn = new PDO("mysql:host=$servername;dbname=mydatabase", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
   }
    catch(PDOException $e)
   {
   echo "Connection failed: " . $e->getMessage();
   }



  // strip tags may not be the best method for your project to apply extra 
   layer of security but fits needs for this tutorial 
   $search = strip_tags(trim($_GET['q'])); 

 // Do Prepared Query
   $query = $conn->prepare("
   SELECT * FROM (
    SELECT wp_terms.name
   FROM wp_terms
   JOIN wp_term_taxonomy
    ON wp_term_taxonomy.term_id = wp_terms.term_id
    WHERE taxonomy = 'job_listing_region'
    AND count = 0
    ) as T"
     );

    // Add a wildcard search to the search variable
     $query->execute(array(':search'=>"%".$search."%"));


   // Do a quick fetchall on the results
    $list = $query->fetchall(PDO::FETCH_ASSOC);

   // Make sure we have a result
   if(count($list) > 0){
    foreach ($list as $key => $value) {
    $data[] = array('id' => $value['name'], 'text' => $value['name']);              
   } 
    } else {
   $data[] = array('id' => '0', 'text' => 'No Products Found');
   }


// return the result in json
echo json_encode($data);

提前致谢。

Select2 Ajax查询未检索结果

0 个答案: