Question

当var [5]从＆＃34;＆＃34;更改时，while循环不会停止到＆＃34;离开＆＃34;或＆＃34;对＆＃34;

#Variable Input
name = input("Enter your name: ")
place = input("Enter where you live: ")
sex = input("Are you a boy (Y/N): ")
scaryanimal = input("Enter the type of animal that you are most scared of: ")
happyanimal = input("Enter your favourite type of animal: ")
var=[name,place,sex,scaryanimal,happyanimal,""]

#Main story

#Other code goes here

#Offending While loop

while var[5].lower() != "left" or var[5].lower() != "right": 
        var[5] = input("Did he go left or right: ")
        print(var[5])

Answer 1

我读到你说你的变量正在改变，但在哪里？

两件事：您必须更改您正在检查的变量并且您必须更改该条件测试，当变量True为var[5]时，循环条件为while var[5].lower() != "left" and var[5].lower() != "right": var[5] = input("Did he go left or right: ") print(var[5])不同于＆＃39; left＆＃39;或者不正确的＆＃39; （如果它＆＃34;离开＆＃34;，那么它与＆＃39;右边＆＃39;不同，所以循环将继续）

因此...

function pushAtStarting(array, element){
    array.unshift(element); // new element has s.no = 0
    for (index in array){
       array[index].sno++
    }
}
var array = [];
pushAtStarting(array, {sno: 0, description: "abc"});

Python变量时循环不会结束

1 个答案: