我正在尝试在Python中的shapefile中绘制一些区域的地图。我的基本方法是:
shp = fiona.open("C:/Users/nils/Documents/Maps/my_shapefile.shp")
bds = shp.bounds
ll = (bds[0], bds[1])
ur = (bds[2], bds[3])
coords = list(ll + ur)
w, h = coords[2] - coords[0], coords[3] - coords[1]
# Make figure instance, add Basemap and CCG boundaries from shapefile
fig, ax = plt.subplots(figsize=(12,10))
m = Basemap(projection="tmerc", lon_0 = -2., lat_0 = 49., ellps="WGS84",
llcrnrlon = coords[0], llcrnrlat = coords[1],
urcrnrlon = coords[2], urcrnrlat = coords[3],
lat_ts = 0, resolution="i", suppress_ticks=True)
m.readshapefile("C:/Users/nils/Documents/Maps/my_shapefile.shp", "Regions")
# Extract polygon coordinates of and names of regions to plot from shapefile
to_plot = ["region_A", "region_B", "region_C"]
poly = []; name = []
for coordinates, region in zip(m.Regions, m.Regions_info):
if any(substr in region["name"] for substr in to_plot):
poly.append(Polygon(coordinates))
name.append(region["name"])
# Turn polygons into patches using descartes
patches = []
for i in poly:
patches.append(PolygonPatch(i, facecolor='#006400', edgecolor='#787878', lw=0.25, alpha=0.5))
# Add PatchCollection to basemap
ax.add_collection(PatchCollection(patches, match_original=True))
现在我的问题是shapefile覆盖了更大的地理区域,但我只想绘制这个区域的一个子集(想想我有一个英国的shapefile,但想绘制威尔士所有地区的地图) 。现在我可以识别正确的区域,并且只添加这些补丁,如上例所示,但是matplotlib仍将绘制shapefile中所有区域的边界,而fiona的bounds
方法识别的边界显然与子集无关我选择的补丁。
我有两个与此相关的问题:
如何让matplotlib仅绘制shapefile中定义的补丁子集的边界?
如何获取补丁子集的边界,类似于fiona的bound
方法对整个shapefile的作用?
答案 0 :(得分:2)
为了回答第二部分,这里有一个能够达到预期结果的功能:
def get_bounds(patch_list):
m = Basemap()
# Read in shapefile, without drawing anything
m.readshapefile("C:/Users/ngudat/Documents/Maps/CCG/CCG_boundaries_2015", "patches", drawbounds=False)
# initialize boundaries (this is a bit of a manual step, might be better to intialize to boundaries of first patch or something)
lon_min = 0.
lon_max = -3.
lat_min = 60.
lat_max = 0.
for (shape, patch_name) in zip(m.patches, m.patches_info):
if patches["name"] in patch_list:
lon, lat = zip(*shape)
if min(lon) < lon_min:
lon_min = min(lon)
if max(lon) > lon_max:
lon_max = max(lon)
if min(lat) < lat_min:
lat_min = min(lat)
if max(lat) > lat_max:
lat_max = max(lat)
return lon_min, lat_min, lon_max, lat_max
可能不是最有效的方法,并且可能需要更改初始化步骤,但这个想法应该适用于类似情况。
答案 1 :(得分:0)
要(部分)回答我的第一个问题,实现这一目标的方法是用readshapefile
拨打drawbounds=False
;在这种情况下,地图上不会有任何边界,但在任何情况下,我会选择区域的边界。