任何人都可以在yii2 ???
中构建此子查询//*[@id="approvalConfirm"]
帮助很明显!! 在此先感谢!!
答案 0 :(得分:3)
您可以使用activequery
..
$query= (new Query())->select([
'name' ,
'crt_by' ,
'employee' => (new Query())->select('name')
->from('tbl_employee_master')
->where([
'=','tbl_employee_master.contact', (new Query())
->select('username')
->from('tbl_user')
->where('tbl_user.id=tbl_dealer_master.crt_by')
]),
'district',
'contact_person',
'contact',
'post_count' => (new Query())->select('count(*)')
->from('tbl_dealer_post')
->where('tbl_dealer_post.fk_user_id=tbl_dealer_master.id')
])->from('tbl_dealer_master')->where(['status' => 1]);
答案 1 :(得分:-2)
这是给定问题的完整解决方案!!
$query= (new Query())->select([
'name' ,
'crt_by' ,
'employee' => (new Query())->select('name')
->from('tbl_employee_master')
->where([
'=','tbl_employee_master.contact', (new Query())
->select('username')
->from('tbl_user')
->where('tbl_user.id=tbl_dealer_master.crt_by')
]),
'district',
'contact_person',
'contact',
'post_count' => (new Query())->select('count(*)')
->from('tbl_dealer_post')
->where('tbl_dealer_post.fk_user_id=tbl_dealer_master.id')
])->from('tbl_dealer_master')->where(['status' => 1]);