Question

我有一个表tblPerson和列fullname

--------------
fullname   
--------------
Garcia, John C.
Herdan, Stephen S.
Ubico, Ed Z.

我想爆炸全名列以获取最后一个，第一个和中间名并分别创建3个列。

我正在使用MS SQL Server 2008 R2

输出：

------------------------------------------------------------------------
   fullname              lname             fname               mname
------------------------------------------------------------------------
Garcia, John C.          Garcia,           John                C.
Herdan, Stephen S.       Herdan,           Stephen             S.
Ubico, Ed Z.             Ubico,            Ed                  Z.

提前感谢

Answer 1

最简单的解决方案是，

SELECT fullname,REVERSE(PARSENAME(REPLACE(REVERSE(fullname) ,' ' ,'.') ,1)) AS lname
      ,REVERSE(PARSENAME(REPLACE(REVERSE(fullname) ,' ' ,'.') ,2)) AS fname
      ,REVERSE(PARSENAME(REPLACE(REVERSE(fullname) ,' ' ,'.') ,3)) AS mname
FROM   tblPerson

或

SELECT fullname,REVERSE(PARSENAME(REPLACE(REVERSE(fullname) ,' ' ,'.') ,1)) AS lname ,REVERSE(PARSENAME(REPLACE(REVERSE(fullname) ,' ' ,'.') ,2)) AS fname ,STUFF(fullname, 1, Len(fullname) +1- CHARINDEX(' ',Reverse(fullname)), '') mname FROM tblPerson

sql fiddle demo

Answer 2

这个将支持多字的姓氏和名字：

$rootScope

Answer 3

尝试;

;with data_tbl as (
    select [fullname],
    CHARINDEX(',', [fullname]) + 1 index_comma,
    CHARINDEX(' ', [fullname], CHARINDEX(',', [fullname]) + 2) index_space,
    len([fullname]) len_name
    from tblPerson
    --where [fullname] like '%, % %'
)
select 
    [fullname],
    left([fullname], index_comma - 1) lname,
    substring([fullname], index_comma, index_space - index_comma) fname,
    substring([fullname], index_space, len_name) mname
from data_tbl

sql fiddle demo

如果您添加where条件where [fullname] like '%, % %'，那么它将忽略fromat fullname

中不存在的所有%, % %

SQL：将列值分隔为多个列

3 个答案: