Question

当我的应用处于活动状态时，我使用alertview显示通知，当我的应用处于非活动状态时，我想显示通知。

这是我的回答：

aps =     {
        alert =         {
            calltype = order;
            id = 194;
            info = "Dear Customer Thank you for contacting SR number for your request is SACHA4 We will contact you shortly with our service professional details.";
        };
        sound = default;
    };

我正在拆分像这样的值：

NSDictionary *aps=[userInfo objectForKey:@"aps"];
    NSDictionary *alertdic=[aps objectForKey:@"alert"];

非活动状态编码：

if (application.applicationState == UIApplicationStateInactive)
    {

        query=[NSString stringWithFormat:@"insert into job ('id','message','calltype')values('%ld','%@','%@')",[[alertdic objectForKey:@"id"] integerValue],[alertdic objectForKey:@"info"],[alertdic objectForKey:@"calltype"]];

        UILocalNotification *notification = [[UILocalNotification alloc] init];
        notification.alertBody = [alertdic objectForKey:@"message"];
        notification.applicationIconBadgeNumber = 0;

        [[UIApplication sharedApplication] scheduleLocalNotification:notification];


    }

但是通知没有到达，但是通知声音到了。我需要你的帮助朋友。

Answer 1

如果您的应用程序位于Inactive status，那么您无法在此时向用户显示任何警告，系统通知中将向用户显示默认系统通知。因此，在处于停用状态时，您必须使用解析推送（或您使用的任何内容）注册您的应用程序，并且会发送用户通知，但是当用户点击该通知时，您可以检查此条件if (application.applicationState == UIApplicationStateInactive)，在此您可以向用户显示提醒或重定向到任何特定页面。

Answer 2

我的服务器响应这是我们之前的回复：

aps =     {
        alert =         {
            calltype = order;
            id = 194;
            info = "Dear Customer Thank you for contacting SR number for your request is SACHA4 We will contact you shortly with our service professional details.";
        };
        sound = default;
    }

现在我们将此更改为喜欢这个

aps =     {
        alert = "Dear Customer Thank you for contacting SR number for your request is SACHAS We will contact you shortly with our service professional details.";
        calltype = order;
        id = 194;
        sound = default;
    };

应用程序无效状态通知未到达？

2 个答案: