将值表单变量放入触发器后，Oracle 11g XE忽略了我的语句

Question

我希望从Doctor和Department表中获取规范，以确保部门经理在插入时具有相同的规范..

create or replace TRIGGER check_dept_man
After Insert on DEPARTMENT
FOR EACH ROW
DECLARE
spec Varchar2(30);
dept_name Varchar2(30);
BEGIN
dept_name := :new.DEPT_NAME;
SELECT DR_SPECIALISATION INTO spec from DOCTOR where DR_ID= :new.MANAGER_ID;
IF ( dept_name != spec ) THEN
raise_application_error(-20353,"error man");
END IF;
END;

这是我得到的错误：

这是部门表：

CREATE TABLE  "DEPARTMENT" 
   (    "DEPT_ID" NUMBER(3,0), 
    "DEPT_NAME" VARCHAR2(30), 
    "MANAGER_ID" NUMBER(3,0), 
    "MANAGE_DATE" DATE, 
    "LOCATION" VARCHAR2(6), 
    "NUMBER_OF_DOCTORS" NUMBER(3,0), 
    "NUMBER_OF_NURSES" NUMBER(3,0), 
    CONSTRAINT "DEPT_ID_PK" PRIMARY KEY ("DEPT_ID") ENABLE, 
    CONSTRAINT "DEPT_NAME_UQ" UNIQUE ("DEPT_NAME") ENABLE
    ) ;

这是医生：

CREATE TABLE  "DOCTOR" 
   (    "DR_ID" NUMBER(5,0), 
"DR_NAME"  "FULL_NAME" , 
"DR_GENDER" VARCHAR2(6), 
"DR_SPECIALISATION" VARCHAR2(30), 
"DR_LOCATION"  "LOCATION_TY" , 
"DEPT_NO" NUMBER(3,0), 
"TOTAL_SURGERY_TIME" NUMBER(4,0), 
 CONSTRAINT "DR_GENDER_IS" CHECK (dr_gender IN ('Male','Female')) ENABLE, 
 CONSTRAINT "DR_ID_PK" PRIMARY KEY ("DR_ID") ENABLE
  ) ;
 ALTER TABLE  "DOCTOR" ADD CONSTRAINT "DR_DEPT_FK" FOREIGN KEY ("DEPT_NO")
  REFERENCES  "DEPARTMENT" ("DEPT_ID") 

整件事就是这个'而且这......我花了一整天的时间来处理这个愚蠢的错误..谢谢@kordirko和你们所有的人

Answer 1

感谢@kordirko观察，它应该有效：

CREATE OR REPLACE TRIGGER check_dept_man
    BEFORE INSERT ON DEPARTMENT
    FOR EACH ROW
DECLARE
    spec Varchar2(30);
    dept_name Varchar2(30);
BEGIN
    dept_name := :new.DEPT_NAME;
    SELECT DR_SPECIALISATION INTO spec from DOCTOR where DR_ID= :new.MANAGER_ID;
    IF dept_name != spec THEN
        raise_application_error(-20353, 'error man');
    END IF;
END;
/