我试图通过按下复选框按钮来更改textarea的占位符。我无法让它改变。
要清楚,我试图设置占位符而不是值。
我的textarea:
<textarea name="problem" id="problem" rows="3" class="form-control" cols="45" placeholder="Describe your ticket reason in as few words as possible."></textarea>
我的JavaScript:
<div class="onoffswitch">
<input type="checkbox" onchange="changeplh()" name="onoffswitch" class="onoffswitch-checkbox" value="1" id="myonoffswitch" checked>
<label class="onoffswitch-label" for="myonoffswitch">
<span class="onoffswitch-inner"></span>
<span class="onoffswitch-switch"></span>
</label>
<script>
function changeplh(){
debugger;
var sel = document.getElementById("myonoffswitch");
var textbx = document.getElementById("problem");
var indexe = sel.selectedIndex;
if(indexe == 0) {
$("#problem").val('');
$("#problem").prop("placeholder", "age");
}
if(indexe == 1) {
$("#problem").val('');
$("#problem").prop("placeholder", "name");
}
}
</script>
</div>
我特别需要的 - 一个复选框按钮,用于将textarea的占位符更改为2个不同的选项。 EX:点击一次,它会显示&#34;年龄&#34;再次点击它会显示&#34; name&#34 ;,再次点击它会显示&#34; age&#34;等
答案 0 :(得分:2)
您的代码有点混乱(例如,您的代码中没有#problem
)因此我创建了一个更改placeholder
的简单演示。
$('#problem').change(function() {
$('textarea').attr('placeholder', $(this).is(':checked') ? 'name' : 'age');
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<textarea class="form-control" style="height:150px" name="techProblem" placeholder="Describe the issue in as few words as possible."></textarea>
<label><input type="checkbox" id="problem" /> Change placeholder</label>