是的，PSJobs是真正的“背景”工作。

Question

我正在尝试实现在用户单击按钮后启动的后台命令，到目前为止，我总是在作业正在进行时将我的UI锁定。我目前正在使用一个耗时的for循环来检查我的UI是否锁定。当UI被释放时，我可以做些什么来让工作在后台工作。我不确定我是否想通过添加运行空间来使代码复杂化。我做错了什么？

$inputXML = @"
<Window x:Class="WpfApplication2.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:WpfApplication2"
        mc:Ignorable="d"
        Title="Create User" Height="448.05" Width="656.017" ResizeMode="NoResize">
    <Grid Margin="0,0,-6.8,-0.8" Background="#FFD7D7D7">
        <Grid.RowDefinitions>
            <RowDefinition Height="403*"/>
            <RowDefinition Height="18*"/>
        </Grid.RowDefinitions>
        <Grid.ColumnDefinitions>
            <ColumnDefinition/>
        </Grid.ColumnDefinitions>
        <Button x:Name="Create_User" Content="Create User" HorizontalAlignment="Left" Margin="67,224,0,0" VerticalAlignment="Top" Width="300" Height="26" RenderTransformOrigin="0.551,-0.671" IsEnabled="True">
            <Button.Background>
                <LinearGradientBrush EndPoint="0,1" StartPoint="0,0">
                    <GradientStop Color="#FFF3F3F3" Offset="0"/>
                    <GradientStop Color="#FFEBEBEB" Offset="0.5"/>
                    <GradientStop Color="#FFDDDDDD" Offset="0.5"/>
                    <GradientStop Color="#FFCDCDCD" Offset="1"/>
                </LinearGradientBrush>
            </Button.Background>
        </Button>
        <Label x:Name="fname" Content="" HorizontalAlignment="Left" Margin="43,11,0,0" VerticalAlignment="Top" Height="26" Width="10"/>
        <Label x:Name="fname1" Content="First Name" HorizontalAlignment="Left" Margin="88,54,0,0" VerticalAlignment="Top" Width="72" RenderTransformOrigin="0.513,1.469" Height="26"/>
        <Label x:Name="lname" Content="Last Name" HorizontalAlignment="Left" Margin="88,83,0,0" VerticalAlignment="Top" RenderTransformOrigin="-0.167,-0.458" Width="72" Height="25"/>
        <TextBox x:Name="fnametxt" Height="23" Margin="167,54,0,0" TextWrapping="Wrap" VerticalAlignment="Top" RenderTransformOrigin="0.501,0.452" HorizontalAlignment="Left" Width="136"/>
        <Button x:Name="exitbtn" Content="Exit" HorizontalAlignment="Left" VerticalAlignment="Top" Width="135" Margin="447,365,0,0" Height="38" RenderTransformOrigin="0.489,0.462"/>
        <Label x:Name="label" Content="Password" HorizontalAlignment="Left" Margin="92,113,0,0" VerticalAlignment="Top" RenderTransformOrigin="0.064,0.601" Height="26" Width="68"/>
        <PasswordBox x:Name="passwordBox" Margin="167,113,0,0" VerticalAlignment="Top" Height="24" HorizontalAlignment="Left" Width="136"/>
        <TextBox x:Name="stsbox" HorizontalAlignment="Left" Height="62" Margin="67,267,0,0" TextWrapping="Wrap" VerticalAlignment="Top" Width="300" Background="#FFDADADA" Foreground="Black" Opacity="0.45" SelectionBrush="#FF1D6EBF" RenderTransformOrigin="0.503,-0.59" IsReadOnly="True"/>
        <TextBox x:Name="lnametxt" Height="23" Margin="167,85,0,0" TextWrapping="Wrap" VerticalAlignment="Top" HorizontalAlignment="Left" Width="136"/>
    </Grid>
</Window>
"@ 

$inputXML = $inputXML -replace 'mc:Ignorable="d"','' -replace "x:N",'N'  -replace '^<Win.*', '<Window'
[void][System.Reflection.Assembly]::LoadWithPartialName('presentationframework')
[void][System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
[xml]$xaml = $inputXML

#Read XAML
$reader=(New-Object System.Xml.XmlNodeReader $xaml) 
try{$Form=[Windows.Markup.XamlReader]::Load( $reader )}
catch{Write-Host "Unable to load Windows.Markup.XamlReader. Double-check syntax and ensure .net is installed."}
$xaml.SelectNodes("//*[@Name]") | %{Set-Variable -Name "WPF$($_.Name)" -Value $Form.FindName($_.Name) -Scope Global}


Function global:Get-FormVariables{
if ($global:ReadmeDisplay -ne $true) {$global:ReadmeDisplay=$true}
#write-host "Found the following interactable elements from our form" -ForegroundColor Cyan
get-variable WPF*
} 


Get-FormVariables


 $WPFCreate_User.Add_Click({

$test = { for($i=1; $i -le 100000; $i++){
$z = $i + $z
$z
}}

$job = Start-Job $test 
Wait-Job $job

Receive-Job $job -OutVariable results
Remove-Job $job
$WPFstsbox.text = "$results`n"
                           }) 

 $WPFexitbtn.add_click({
 $form.Close() | out-null
 exit})

$form.ShowDialog() | Out-null

Answer 1

是的，PSJobs是真正的“背景”工作。

当您致电$member = $this->domainObjectFactory->getMember();时，会启动单独进程，执行您的作业/命令。

在您的脚本中，作业本身不会阻止调用线程，但后续命令（Start-Job）会阻塞。

如果你只是关闭Wait-Job $job并从Start-Job处理程序返回，那么你的用户界面就不会锁定：

Click

你会看到用户界面再次以超过10秒的速度响应。

问题是您无法再访问$button.add_Click({ $jobCode = { Start-Sleep -Seconds 10 } $job = Start-Job $jobCode })，也无法再控制何时显示。

为了弥补这一点，您需要后台线程或定时事件，可以定期检查您的工作并输出结果。

您可以使用$job和PowerShell的内置事件基础架构：

Timer

乔布斯真的在后台工作吗？

1 个答案:

是的，PSJobs是真正的“背景”工作。