Question

我试图将MySQL表的内容转换为CSV文件。一切正常，除了在我通过Array的标题标签之前插入一个空行。

 <?php
    error_reporting(0);
    ob_start();
    session_start();
    include 'auto_logout.php';
    //echo $_SESSION['fullname'];
    if ((!isset($_SESSION['ufullname'])) && (!isset($_SESSION['fullname']))) {
        /* Redirect browser */
        header("Location: index.php");
        /* Make sure that code below does not get executed when we redirect. */
        exit();
    }
    $output = "";
    require_once('config/config.php');
    require_once("includes/ftp_settings.php");
    $table = "Download CSV"; // Enter Your Table Name 
    if (is_array($new_exist) && (is_array($ftp1))) {
        $ressd_new = 'select filename from files where uploaded_by IN ("' . implode('","', $new_exist) . '")';
        $resd_new  = mysql_query($ressd_new);
        while ($kkk_new = mysql_fetch_array($resd_new)) {
            $gotit_new = $kkk_new[0];
        }

        $resultka_new = $ftp1;

        $sql = 'SELECT slno, filename, uploaded_by, dateadded, timeadded, size FROM files where uploaded_by IN ("' . implode('","', $new_exist) . '") and filename IN ("' . implode('","', $resultka_new) . '") and size != "0"';

    } else {

        $sql = "SELECT slno, filename, uploaded_by, dateadded, timeadded, size FROM files where ftp_file  = '$ftp_server' and ftp_u_file = '$ftp_user_name' and ftp_p_file = '$ftp_user_pass' and size != '0'";

    }
    $sql           = mysql_query($sql);
    $columns_total = mysql_num_fields($sql);

    // Get The Field Name
    $heading1 = array(
        "Sl. No.",
        "File Name",
        "Uploaded By",
        "Date Added",
        "Time Added",
        "Size"
    );
    $inc = 0;
    for ($i = 0; $i < $columns_total; $i++) {
        $heading = $heading1[$inc];
        $output .= '"' . $heading . '",';
        $inc = $inc + 1;
    }
    $output .= "\n";

    // Get Records from the table

    while ($row = mysql_fetch_array($sql)) {
        for ($i = 0; $i < $columns_total; $i++) {
            $output .= '"' . $row["$i"] . '",';
        }
        $output .= "\n";
    }

    // Download the file

    $filename = "myFile.csv";
    header('Content-type: application/csv');
    header('Content-Disposition: attachment; filename=' . $filename);

    echo $output;
    exit;

?>

不确定来自哪里的空白行。

Answer 1

如果没有正确关注，包含文件通常会添加不需要的空格。抑制错误会使事情变得更糟。

你需要ob_start（）的原因是因为ob_start（）和“echo $ output;”之间的脚本正在打印一些内容（可能是空行）。因此，您无法设置标题。我敢打赌它在你包含的文件中（auto_logout，config，ftp_settings）。

允许错误，删除ob_start，解决所有警告，获利。

顺便说一下：不要使用mysql扩展名，而是使用mysqli。

使用PHP MySQL

1 个答案: