我有这段代码:
if (PsionTeklogix.Keyboard.Keyboard.GetModifierKeyState(Key.Orange) == KeyState.Lock)
PsionTeklogix.Keyboard.Keyboard.InjectKeyboardCommand(Function.Orange, 0, 0);
if (PsionTeklogix.Keyboard.Keyboard.GetModifierKeyState(Key.Blue) == KeyState.Lock)
PsionTeklogix.Keyboard.Keyboard.InjectKeyboardCommand(Function.Blue, 0, 0);
if (PsionTeklogix.Keyboard.Keyboard.GetModifierKeyState(Key.Shift) == KeyState.Lock)
PsionTeklogix.Keyboard.Keyboard.InjectKeyboardCommand(Function.Shift, 0, 0);
if (PsionTeklogix.Keyboard.Keyboard.GetModifierKeyState(Key.Control) == KeyState.Lock)
PsionTeklogix.Keyboard.Keyboard.InjectKeyboardCommand(Function.Control, 0, 0);
...
我想重构分离键/函数定义的代码 动作。 Key.xxx和Function.xxx不是同一类型。
例如:在Python中,我可以简单地执行以下操作:
keys = (
( Key.Orange, Function.Orange ),
( Key.Blue , Function.Blue ),
( Key.Shift , Function.Shift ),
...
)
psi_key = PsionTeklogix.Keyboard.Keyboard
for key, func in keys:
if psi_key.GetModifierKeyState(key) == KeyState.Lock):
psi_key.InjectKeyboardCommand(func, 0, 0)
在C#中做什么是“正确的方法”?
答案 0 :(得分:13)
你可以做一些非常相似的事情:
Dictionary<Key, Function> keys = new Dictionary<Key, Function>
{
{ Key.Orange, Function.Orange },
{ Key.Blue, Function.Blue }
...
};
foreach (var pair in keys)
{
if (Keyboard.GetModifierKeyState(pair.Key) == KeyState.Locked)
{
Keyboard.InjectKeyboardCommand(pair.Value, 0, 0);
}
}
如果您愿意,甚至可以使用LINQ:
foreach (var pair in keys.Where(pair =>
Keyboard.GetModifierKeyState(pair.Key) == KeyState.Locked)
{
Keyboard.InjectKeyboardCommand(pair.Value, 0, 0);
}
现在使用Dictionary
有点奇怪,因为我们没有找到任何东西。如果您使用的是.NET 4,则可以使用元组列表:
var keys = new List<Tuple<Key, Function>>()
{
Tuple.Of(Key.Orange, Function.Orange),
Tuple.Of(Key.Blue, Function.Blue),
...
};
并相应地调整循环。您也可以使用匿名类型:
var keys = new[]
{
new { Key = Key.Orange, Function = Function.Orange },
new { Key = Key.Blue, Function = Function.Blue },
...
};
它们基本上都是表示键/函数对的方式:)
答案 1 :(得分:1)
假设Key和Function是枚举,您也可以尝试:
foreach (Key key in Enum.GetValues(typeof(Key)))
{
if (PsionTeklogix.Keyboard.Keyboard.GetModifierKeyState(key) == KeyState.Lock)
{
PsionTeklogix.Keyboard.Keyboard.InjectKeyboardCommand((Function)Enum.Parse(typeof(Function), key.ToString()), 0, 0);
}
}
答案 2 :(得分:1)
using PsionTeklogix.Keyboard; /* assuming that's a namespace, */
/* otherwise, you can optionally do: */
/* using Keyboard = PsionTeklogix.Keyboard.Keyboard; */
class Foo{
static readonly Key[] keys = {Key.Orange, Key.Blue, Key.Shift, ...};
static readonly Function[] functions = {Function.Orange, Function.Blue, Function.Shift, ...};
static void Main(){
for(int i = 0; i < keys.Length; i++)
if(Keyboard.GetModifierKeyState(keys[i]) == KeyState.Lock)
Keyboard.InjectKeyboardCommand(func, 0, 0);
}
}
或者,由于看起来Key
和Function
都是枚举,和,因此每个{{1}使用相同的Function
枚举值名称}枚举值,你可以做这样的事情,这稍微漂亮,如果稍微慢一些:
Key
好吧,也许它不漂亮。 MEH。
但是,如果static readonly string[] values = {"Orange", "Blue", "Shift", ...};
static void Main(){
foreach(string value in values)
if(Keyboard.GetModifierKeyState((Key)Enum.Parse(typeof(Key), value)) == KeyState.Lock);
Keyboard.InjectKeyboardCommand((Function)Enum.Parse(typeof(Function), value), 0, 0);
}
的值也与Key
的值相同(即Function
等),那么你可以这样做:
(int)Key.Orange == (int)Function.Orange
这些都不是Python代码的 direct 等价物,更像是这样:
static readonly Key[] keys = {Key.Orange, Key.Blue, Key.Shift, ...};
static void Main(){
foreach(Key key in keys)
if(Keyboard.GetModifierKeyState(key) == KeyState.Lock);
Keyboard.InjectKeyboardCommand((Function)key, 0, 0);
}
这是所有人中最详细的解决方案,但它是最灵活的。
答案 3 :(得分:0)
您可以使用Dictionary
。
Dictionary<Key, Function> map = new Dictionary<Key, Function>();
map.Add(Key.Orange, Function.Orange);
map.Add(Key.Blue, Function.Blue);
map.Add(Key.Shift, Function.Shift);
map.Add(Key.Control, Function.Control);
foreach(var pair in map)
{
if (PsionTeklogix.Keyboard.Keyboard.GetModifierKeyState(map.Key) == KeyState.Lock)
{
PsionTeklogix.Keyboard.Keyboard.InjectKeyboardCommand(map.Value, 0, 0);
}
}