Question

尝试使用php curl get请求访问api。要使get请求生效，我必须首先使用post请求进行身份验证，实际上是登录到平台。我从发布请求中得到了正确的答复，但我无法获得get请求。这是我的代码：

<?php

  $login_url = "https://publisher-api.company.com/1.0/Publisher/Login";
  $user_pswd = array(
    "username" => "username1",
    "password" => "password1"
  );

  $report_url = "https://publisher-api.company.com/1.0/Publisher(#####)/Channels/RevenueReport";

  function httpGet($url)
  {
    $ch = curl_init();

    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    // curl_setopt($ch, CURLOPT_HEADER, true);

    $output = curl_exec($ch);

    if($output === false)
    {
      echo "Error Number:".curl_errno($ch)."<br>";
      echo "Error String:".curl_error($ch);
    }
    echo $output;

  }

  function httpPost($url_post, $params, $url_get)
  {
    foreach($params as $key=>$value) { $params_string .=$key.'='.$value.'&'; }
    rtrim($params_string, '&');

    $ch = curl_init();

    curl_setopt($ch, CURLOPT_URL, $url_post);
    curl_setopt($ch, CURLOPT_POST, count($params));
    curl_setopt($ch, CURLOPT_POSTFIELDS, $params_string);

    $result = curl_exec($ch);
    echo $result;

    httpGet($url_get);

    curl_close($ch);
  }

  httpPost($login_url, $user_pswd, $report_url);

?>

这是回显的输出：

{"value":{"publisher":{"active":"1","publisher_id":"#####"}}}1{"error":{"code":"SYSTEM.SERVICE.NOT_AUTHORIZED","message":"You are not authorized to use this service. Authenticate first."}}

Answer 1

在页面顶部设置error_reporting(E_ALL)
当您致电httpGet($urlG);时，$urlG在名为httpPost()
＃1会阻止＃2
我的眼睛在$uurl，pparams等网站流血......请让这些变量名更有意义

PHP Curl Get Request失败，错误编号为3，网址格式错误

1 个答案: