如何在selenium webdriver中安全地处理弹出窗口

时间:2016-01-05 15:37:28

标签: java selenium-webdriver popup

我尝试了很多解决方案,但没有一个能为我工作。我有一个页面打开弹出窗口,当我尝试使用该弹出窗口执行任何操作时,它表示元素不可见。

根据情况,首先需要花费时间来加载数据,如下图所示Popup_1,然后它显示数据如下图所示Popup_2。

我试图把不关闭弹出窗口的条件设置为我得到文字“成功:”。

enter image description here enter image description here

我的代码:

 for (String handle : driver.getWindowHandles()) {
    driver.switchTo().window(handle);}


    WebDriverWait waitforEle = new WebDriverWait(driver, 300);
    waitforEle.until(ExpectedConditions.visibilityOfAllElementsLocatedBy(By.xpath("//*[@id='divc8fff3cf6a']/div[1]/strong")));              
    driver.findElement(By.xpath("//*[@id='modal']/div[1]/a")).click();          

弹出式HTML代码:

<div class="modal fade in" id="modal" style="display: block;"><div class="modal-header"><a class="close" href="#" data-dismiss="modal">×</a><h3>Delete Listings</h3></div><div class="inner"><div id="divc8fff3cf6a">
    <div class="alert alert-success fade in">
  <button class="close" data-dismiss="alert">×</button>
  <strong>Success:</strong> 1 products have been queued for removal from Amazon.</div>    <div class="modal-footer">
        <a href="#" class="btn btn-small" onclick="location.reload()">Close</a>    </div>
</div><script>
//<![CDATA[
window.customModal = {"formUUID":"#formfbe89bf4a5","modalUUID":"#divc8fff3cf6a"};
if(typeof window.customModal != 'undefined'){
    $(window.customModal["formUUID"]).on("submit", function(e){
        e.preventDefault();
        $.ajax({
            cache: false,
            method: "POST",
            data: $(this).serialize(),
            url: $(this).attr("action"),
            before: function(){
                window.modal.close();
                window.loading.show();
            },
            success: function(data, textStatus){
                window.loading.close();
                window.modal.options["content"] = data;
                window.modal.show();
            }
        });

        return false;
    });

    $(".resubmit").on("click", function(e){
        window.modal.close();
        $(window.app[$(this).data("resubmit")]).trigger("submit");
    });
}
//]]>
</script></div></div>

1 个答案:

答案 0 :(得分:0)

试试这个

if(alert.getText().contains("Success:"))

  alert.dismiss();