Question

我想知道是否有办法根据其位置缩放精灵节点？

因此，例如当角色y位置增加时，你希望他看起来更小，就像他走得更远。当他的y位置减少时，你希望他越接近你就越大。

let swipeUp = UISwipeGestureRecognizer()

override func didMoveToView(view: SKView) {

    swipeUp.addTarget(self, action: "swipedUp")
    swipeUp.direction = .Up
    self.view!.addGestureRecognizer(swipeUp)

    swipeDown.addTarget(self, action: "swipedDown")
    swipeUp.direction = .Down
    self.view!.addGestureRecognizer(swipeDown)

    addSprite()
}

func swipedUp(){


  let amountToMove: CGFloat = 100
  let move: SKAction = SKAction.moveByX(0, y: amountToMove, duration: 0.1)

  character.runAction(move)

}

func swipedDown(){

  let amountToMove: CGFloat = 100
  let move: SKAction = SKAction.moveByX(0, y: -amountToMove, duration: 0.1)

  character.runAction(move)

}

func addSprite(){
     let sprite = SKSpriteNode(imageNamed: "testImage")
     sprite.position = CGPoint(x: xPos, y: yPos)
}

Answer 1

覆盖精灵位置属性并在其中设置比例因子。这是一个非常基本的例子，您需要根据y确定您的比例因子实际是什么。

override var position{
    didSet{
      self.setScale((screen.height - y) / (screen.height / 2))
    }
}

根据位置缩放节点

1 个答案: