我正在制作一个程序,它将通过打印机服务器运行并取消挂起的作业。截至目前,它输出所有内容,我想要做的是排除root
:
输出:
credjet-898837 cdd 5312512 Wed 14 Oct 2015 03:42:32 PM CDT
credjet-898839 cdd 1998848 Wed 14 Oct 2015 03:45:32 PM CDT
credjet-940485 cdd 1206272 Mon 04 Jan 2016 01:10:30 PM CST
credjet-940499 cdd 342016 Mon 04 Jan 2016 01:21:42 PM CST
credjet-940505 cdd 342016 Mon 04 Jan 2016 01:29:26 PM CST
credjet-940509 cdd 342016 Mon 04 Jan 2016 01:38:24 PM CST
credjet-940514 cdd 342016 Mon 04 Jan 2016 02:00:02 PM CST
credjet-940515 cdd 2387968 Mon 04 Jan 2016 02:00:17 PM CST
credjet-940525 cdd 2387968 Mon 04 Jan 2016 02:10:46 PM CST
credjet-940526 cdd 2387968 Mon 04 Jan 2016 02:11:01 PM CST
credjet-940528 cdd 2387968 Mon 04 Jan 2016 02:12:44 PM CST
credjet-940602 cdd 2382848 Mon 04 Jan 2016 02:26:09 PM CST
devljet-931153 siv 1798144 Fri 18 Dec 2015 02:38:30 PM CST
devljet-931157 siv 3278848 Fri 18 Dec 2015 02:47:18 PM CST
devljet-931158 siv 1538048 Fri 18 Dec 2015 02:47:18 PM CST
laser11-917719 root 78848 Wed 18 Nov 2015 09:56:47 PM CST
laser11-918257 root 78848 Thu 19 Nov 2015 09:45:23 PM CST
laser11-918262 root 79872 Thu 19 Nov 2015 09:49:30 PM CST
laser11-918263 root 78848 Thu 19 Nov 2015 09:53:45 PM CST
预期产出:
credjet-898837 cdd 5312512 Wed 14 Oct 2015 03:42:32 PM CDT
credjet-898839 cdd 1998848 Wed 14 Oct 2015 03:45:32 PM CDT
credjet-940485 cdd 1206272 Mon 04 Jan 2016 01:10:30 PM CST
credjet-940499 cdd 342016 Mon 04 Jan 2016 01:21:42 PM CST
credjet-940505 cdd 342016 Mon 04 Jan 2016 01:29:26 PM CST
credjet-940509 cdd 342016 Mon 04 Jan 2016 01:38:24 PM CST
credjet-940514 cdd 342016 Mon 04 Jan 2016 02:00:02 PM CST
credjet-940515 cdd 2387968 Mon 04 Jan 2016 02:00:17 PM CST
credjet-940525 cdd 2387968 Mon 04 Jan 2016 02:10:46 PM CST
credjet-940526 cdd 2387968 Mon 04 Jan 2016 02:11:01 PM CST
credjet-940528 cdd 2387968 Mon 04 Jan 2016 02:12:44 PM CST
credjet-940602 cdd 2382848 Mon 04 Jan 2016 02:26:09 PM CST
devljet-931153 siv 1798144 Fri 18 Dec 2015 02:38:30 PM CST
devljet-931157 siv 3278848 Fri 18 Dec 2015 02:47:18 PM CST
devljet-931158 siv 1538048 Fri 18 Dec 2015 02:47:18 PM CST
#<= No more root
有没有办法可以输出相同的信息,但排除根作业?
来源:
#!/local/usr/bin/ruby
require 'rubygems'
require 'net/ssh'
require 'etc'
class PrintJobs
HOST = '<server here>' #<= Left blank for security
USERNAME = Etc.getlogin
PASSWORD = nil
def scan_for_jobs
check_jobs = Net::SSH.start(HOST, USERNAME, :password => PASSWORD) do |ssh|
cmd = "prt_jobs"
res = ssh.exec!(cmd)
puts res
end
end
end
test = PrintJobs.new
test.scan_for_jobs
答案 0 :(得分:2)
您可以使用以下代码删除不需要的行:
res = ssh.exec!(cmd)
res = res.split("\n").reject {|line| line.match(/\s+root\s+/)}.join("\n")
puts res
exec!
的结果是一个字符串,其中包含通过ssh发出的命令输出。因此,我们需要通过换行拆分它并迭代数组以拒绝包含root
的行,并使用换行重新加入数组。