Question

我正在运行Symfony 2.7.6 dev并且我有一个应该在console.exception上触发的侦听器设置，但是它没有触发，它只像往常一样在控制台中显示异常。出于测试目的，我已经整合了一个console.terminate监听器，它工作正常。（我也测试了console.command，也工作正常）。

对于我的生活，我无法弄清楚为什么console.exception事件不会触发或者为什么console.exception监听器不会触发。

config.yml中的ConsoleExceptionListener设置

kernel.listener.command_dispatch:
        class: CompanyHidden\PortalBundle\Listener\ConsoleExceptionListener
        arguments:  ["@service_container", "@router"]
        tags:
            - { name: kernel.event_listener, event: console.exception, method: onConsoleException }
            - { name: kernel.event_listener, event: console.terminate, method: onConsoleTerminate }

ConsoleExceptionListener.php

<?php

namespace CompanyHidden\PortalBundle\Listener;

use Symfony\Component\HttpKernel\Event\GetResponseForExceptionEvent;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\Console\Event\ConsoleExceptionEvent;
use Symfony\Component\DependencyInjection\ContainerInterface;
use Symfony\Bundle\TwigBundle\TwigEngine;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Template;

class ConsoleExceptionListener
{
    private $container;
    private $router;

    function __construct($container, $router) 
    {
        $this->container = $container;
        $this->router = $router;
    }

    public function onConsoleTerminate()
    {
        die(">>>> TERMINATE TEST >>>>");
    }

    public function onConsoleException(ConsoleExceptionEvent $event)
    {
        die(">>> EXCEPTION TEST<<<<");
    }
}

控制台命令

<?php
namespace CompanyHidden\PortalBundle\Command;

use Symfony\Bundle\FrameworkBundle\Command\ContainerAwareCommand;
use Symfony\Component\Console\Input\InputArgument;
use Symfony\Component\Console\Input\InputInterface;
use Symfony\Component\Console\Input\InputOption;
use Symfony\Component\Console\Output\OutputInterface;

use CompanyHidden\PortalBundle\Classes\ImapMailbox;

class getEmailsCommand extends ContainerAwareCommand
{
    protected function configure()
    {
        $this->setName('getEmails');   
    }

    protected function execute(InputInterface $input, OutputInterface $output)
    {
        $context = $this->getContainer()->get('router')->getContext();
        $context->setScheme('http');

        # SIMULATED TERMINATION TEST
        //print ">>>> TERMINATED <<<<<\n";
        //return null;

        # SIMULATED EXCEPTION TEST
        $null = null;
        $null->getNull();

        //..... Rest of Code, not relevant
    }
}
?>

控制台异常抛出（而不是触发异常监听器）

Answer 1

尝试通过这种方式构建控制台侦听器：

namespace CompanyHidden\PortalBundle\Listener;

use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use Symfony\Component\Console\Event\ConsoleTerminateEvent;
use Symfony\Component\Console\Event\ConsoleExceptionEvent;
use Symfony\Component\Console\ConsoleEvents;

class ConsoleExceptionListener implements EventSubscriberInterface
{
    /.../

    public static function getSubscribedEvents()
    {
        return [
            ConsoleEvents::EXCEPTION => 'onConsoleException',
            ConsoleEvents::TERMINATE => 'onConsoleTerminate'
        ];
    }

    public function onConsoleTerminate(ConsoleTerminateEvent $event)
    {
         die(">>>> TERMINATE TEST >>>>");
    }

    public function onConsoleException(ConsoleExceptionEvent $event)
    {
         die(">>> EXCEPTION TEST<<<<");
    }
}

Answer 2

在控制台文件中，使用$ kernel-＆gt; boot（）;

启动内核

$kernel = new AppKernel($env, $debug);
$application = new Application($kernel);
$kernel->boot();

$kernel->getContainer()->get('event_dispatcher')->addListener(\Symfony\Component\Console\ConsoleEvents::COMMAND,
    function (\Symfony\Component\Console\Event\ConsoleCommandEvent $event) {
        var_dump("COMMAND EVENT");
    });

$kernel->getContainer()->get('event_dispatcher')->addListener(\Symfony\Component\Console\ConsoleEvents::EXCEPTION,
    function (\Symfony\Component\Console\Event\ConsoleExceptionEvent $event) {
        var_dump("EXCEPTION EVENT");
    });

$kernel->getContainer()->get('event_dispatcher')->addListener(\Symfony\Component\Console\ConsoleEvents::TERMINATE,
    function (\Symfony\Component\Console\Event\ConsoleTerminateEvent $event) {
        var_dump("TERMINATE EVENT");
    });


$application->run($input);

Answer 3

Scoolnico的解决方案与symfony 3.3完美配合。有关信息，＆＃39; console.exception＆＃39;事件已被＆＃39; console.error＆＃39;取代在symfony 3.3（https://symfony.com/blog/new-in-symfony-3-3-better-handling-of-command-exceptions）

Answer 4

配置和侦听器看起来正确。

检查您的应用程序/控制台文件，确保已设置调度程序。

应该看起来像这样

$dispatcher = new EventDispatcher();

$kernel = new AppKernel($env, $debug);
$application = new Application($kernel);
$application->setDispatcher($dispatcher);  // <-- Needed for events to work
$application->run($input);

Symfony console.exception不会触发侦听器

4 个答案: