Question

<p>Inspection and treatment will be conducted to areas prone to Mouse infestation by our Service Specialist during the routine visits. This includes the sewerage system servicing the property.</p>

<p>Apart from treating the sewerage manhole, application of residual coat will also be done at strategic areas prone to Mouse activity/harborages, and when necessary, baits will be placed and application of gel will be carried out.</p>

<p>Preparations used are safe to humans and animals and is approved by the Ministry.</p>

上面是我要记录到mysql的文本，我想将它们修改为

<p>Inspection and treatment will be conducted to areas prone to Mouse infestation by our Service Specialist during the routine visits. This includes the sewerage system servicing the property.</p><p>Apart from treating the sewerage manhole, application of residual coat will also be done at strategic areas prone to Mouse activity/harborages, and when necessary, baits will be placed and application of gel will be carried out.</p><p>Preparations used are safe to humans and animals and is approved by the Ministry.</p>

我使用了以下代码：

$service_desc = preg_replace('/\s+/', ' ', $service_desc);

但是代码没有解决字符串文本之间的间距，我怎样才能删除其间的空格来实现我想要的结果。

谢谢！

Answer 1

如果你想删除de end of line字符，这不是更容易吗？

$service_desc = str_replace("\r\n", '', $service_desc);

或

$service_desc = str_replace("\n", '', $service_desc);

很抱歉，如果这不是您的要求。

Answer 2

您可以使用FetchType.EAGER并将CSS设置为0来解决此问题：

margin

<style type="text/css">
p { margin:0 }
</style>

p { margin:0 }

Answer 3

如果要删除标签之间的空格，请使用

$text = preg_replace('/>\s+</', '><', $text);

这也会删除内联标记之间的空格，例如两个相邻的<span>元素，这可能不是您想要的。

PHP Preg替换中间的行

3 个答案: