我一直试图将代码弄清楚一段时间,但是没有成功。每次应用程序崩溃时都会抛出一些随机异常。
我在youtube上的教程中学到了这段代码,尽管如此,代码对我来说并不适用。
import android.content.Context;
import android.net.ConnectivityManager;
import android.net.NetworkInfo;
import android.os.AsyncTask;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
import android.widget.Toast;
import org.w3c.dom.Text;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.MalformedURLException;
import java.net.URL;
import java.nio.Buffer;
import javax.net.ssl.HttpsURLConnection;
public class MainActivity extends AppCompatActivity {
Button b1;
TextView t1;
private Context context;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
b1=(Button)findViewById(R.id.bthhit);
t1=(TextView)findViewById(R.id.tvJSONitem);
b1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
new JSONTask().execute("http://jsonparsing.parseapp.com/jsonData/moviesDemoItem.txt");
}
});
}
public class JSONTask extends AsyncTask<String,String,String>{
HttpsURLConnection connection = null;
BufferedReader reader = null;
@Override
protected String doInBackground(String... params) {
try {
URL url=new URL(params[0]);
connection= (HttpsURLConnection)url.openConnection();
connection.connect();
InputStream stream= connection.getInputStream();
reader = new BufferedReader(new InputStreamReader(stream));
String line;
StringBuffer buffer= new StringBuffer();
while((line=reader.readLine())!=null){
buffer.append(line);
}
return buffer.toString();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(connection!=null) {
connection.disconnect();
}
try {
if(reader!=null){
reader.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
t1.setText(result);
}
}
}
Logcat显示:
01-05 00:46:09.018 5573-5580/? E/art: Failed sending reply to debugger: Broken pipe
01-05 00:46:17.852 5573-5706/com.example.test.jsonparser E/AndroidRuntime: FATAL EXCEPTION: AsyncTask #1
Process: com.example.test.jsonparser, PID: 5573
java.lang.RuntimeException: An error occurred while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:309)
at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:354)
at java.util.concurrent.FutureTask.setException(FutureTask.java:223)
at java.util.concurrent.FutureTask.run(FutureTask.java:242)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:234)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
at java.lang.Thread.run(Thread.java:818)
Caused by: java.lang.ClassCastException: com.android.okhttp.internal.huc.HttpURLConnectionImpl cannot be cast to javax.net.ssl.HttpsURLConnection
at com.example.test.jsonparser.MainActivity$JSONTask.doInBackground(MainActivity.java:58)
at com.example.test.jsonparser.MainActivity$JSONTask.doInBackground(MainActivity.java:49)
at android.os.AsyncTask$2.call(AsyncTask.java:295)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:234)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
at java.lang.Thread.run(Thread.java:818)
01-05 00:46:19.104 5573-5587/com.example.test.jsonparser E/Surface: getSlotFromBufferLocked: unknown buffer: 0xab792110
答案 0 :(得分:22)
请注意,您的网址协议为 HTTP ,而非 HTTPS 。尝试使用 java.net.HttpURLConnection 对象或“https:// ...” URL。
答案 1 :(得分:0)
如果您的应用中不需要某些特定方法,例如.getResponseCode()
或...,那么您也可以使用通用URLConnection
类,这样就不会引入这种异常,因为它是HttpURLConnection
和Https ...类的父类。不知何故。