Question

我有一张表，记录如

id      date       branch
1001    01/01/2015  VBR
1002    02/05/2015  CBR
1001    03/01/2015  VBr
1005    05/05/2015  CBR
1005    12/12/2015  VBR
1006    05/05/2015  CBR

我需要每月明智地选择记录（日期明智），但它应该是唯一的，否则它不应该在任何其他月份例如：如果我选择2015年5月，它应该返回1006

Answer 1

试试这个

SELECT ID FROM 
(
    SELECT 1001 AS ID,   '01/01/2015' AS MY_DATE, 'VBR' AS branch FROM DUAL UNION
    SELECT 1002 AS ID,   '02/05/2015' AS MY_DATE, 'CBR' AS branch FROM DUAL UNION
    SELECT 1001 AS ID,   '03/01/2015' AS MY_DATE, 'VBR' AS branch FROM DUAL UNION
    SELECT 1005 AS ID,   '05/05/2015' AS MY_DATE, 'CBR' AS branch FROM DUAL UNION
    SELECT 1005 AS ID,   '12/12/2015' AS MY_DATE, 'VBR' AS branch FROM DUAL UNION
    SELECT 1006 AS ID,   '05/05/2015' AS MY_DATE, 'CBR' AS branch FROM DUAL
)
where LEFT(CONVERT(varchar, MY_DATE,112),6) = '052015'
GROUP BY ID
HAVING COUNT(ID) = 1

Answer 2

你可以这样试试，

DECLARE @table TABLE
  (
     id     INT,
     date1  DATE,
     branch VARCHAR(10)
  )

INSERT INTO @table
VALUES      ('1001',
             '01/01/2015',
             'VBR'),
            ('1002',
             '02/05/2015',
             'CBR'),
            ('1001',
             '03/01/2015',
             'VBr'),
            ('1005',
             '05/05/2015',
             'CBR'),
            ('1005',
             '12/12/2015',
             'VBR'),
            ('1006',
             '05/05/2015',
             'CBR')

返回所有记录

SELECT *
FROM   @table
WHERE  Year(date1) = 2015
       AND Month(date1) = 5

返回最新记录

SELECT max(id) id
FROM   @table
WHERE  Year(date1) = 2015
       AND Month(date1) = 5 
group by date1

每月选择独特的记录

2 个答案: