尝试在JSON为空时从JSON中提取

时间:2016-01-05 07:58:26

标签: java arrays json parsing

将尝试在此解释我的问题。 我有一个程序,可以解析我从网络爬虫收到的传入JSON文件。

    public static void Scan(Article article) throws Exception
{
    //When running program, creates a error text-file inside java Project folder
    File file = new File("errorlogg.txt");
    FileWriter fileWriter = new FileWriter(file, true);

    // if file doesn't exists, then create it
    if (!file.exists()) 
    {
        file.createNewFile();
    }

    //Setting up an URL HttpURLConnection given DOI
    URL urlDoi = new URL (article.GetElectronicEdition());

    //Used for debugging 
    System.out.println("Initial DOI: " + urlDoi);

    //Transform from URL to String
    String doiCheck = urlDoi.toString();

    //Redirect from IEEE Xplore toe IEEE Computer Society
    if(doiCheck.startsWith("http://dx."))
    {
        doiCheck = doiCheck.replace("http://dx.doi.org/", "http://doi.ieeecomputersociety.org/");
        urlDoi = new URL(doiCheck);
    }

    HttpURLConnection connDoi = (HttpURLConnection) urlDoi.openConnection();

    // Make the logic below easier to detect redirections
    connDoi.setInstanceFollowRedirects(false);  

    String doi = "{\"url\":\"" + connDoi.getHeaderField("Location") + "\",\"sessionid\":\"abc123\"}";

    //Setting up an URL to translation-server
    URL url = new URL("http://127.0.0.1:1969/web");
    URLConnection conn = url.openConnection();

    conn.setDoOutput(true);
    conn.setRequestProperty("Content-Type", "application/json");

    OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());

    writer.write(doi);
    writer.flush();

    String line;
    BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));



    while ((line = reader.readLine()) != null ) 
    {
        //Used to see of we get something from stream
        System.out.println(line);

        //Incoming is JSONArray, so create new array and parse fill it with incoming information
        JSONArray jsonArr = new JSONArray(line);
        JSONObject obj = jsonArr.getJSONObject(0);

        //Check if names from DBLP is the same as translators get
        //AuthorName, from field creators
        JSONArray authorNames = obj.getJSONArray("creators");
        ArrayList<Author> TranslationAuthors = new ArrayList<Author>();

以下是我正在讨论的代码。正如您所看到的,当我从bufferreader获取一些信息时,我想运行此代码。 我的问题是,当我没有获得有效的JSON时,我的程序似乎没有跳过。相反,它运行到这行代码:

        JSONArray authorNames = obj.getJSONArray("creators")

然后被迫退出,因为它无法获得该领域的“创造者”,因为没有。 如何确保我的程序不会遇到此问题?如何轻松地将它放在我创建的错误日志文件中,我无法收集任何信息。

1 个答案:

答案 0 :(得分:2)

我认为您正在使用org.json.JSONObject?如果是这样,则有一个has方法,可用于在密钥不存在时避免使用JSONException

 JSONArray authorNames = null;
 if (obj.has("creators")) {
   authorNames = obj.getJSONArray("creators");
 }