我正在尝试在演示HR模式中找到拥有最多员工的部门:
SELECT d.DEPARTMENT_ID, d.DEPARTMENT_NAME, MAX(COUNT(e.EMPLOYEE_ID))
FROM departments d INNER JOIN employees e ON d.DEPARTMENT_ID = e.DEPARTMENT_ID
GROUP BY d.DEPARTMENT_ID, d.DEPARTMENT_NAME
该脚本不使用MAX()
。
答案 0 :(得分:2)
您可以打包当前查询(减去MAX
)并选择人头数最多的部门组。
WITH CTE (DEPARTMENT_ID, DEPARTMENT_NAME, empCount) AS
(
SELECT d.DEPARTMENT_ID, d.DEPARTMENT_NAME, COUNT(e.EMPLOYEE_ID) AS empCount
FROM departments d INNER JOIN employees e ON d.DEPARTMENT_ID = e.DEPARTMENT_ID
GROUP BY d.DEPARTMENT_ID, d.DEPARTMENT_NAME
)
SELECT DEPARTMENT_ID, DEPARTMENT_NAME
FROM CTE
WHERE empCount = (SELECT MAX(t.empCount) FROM CTE t)
答案 1 :(得分:1)
您可以尝试使用desc on count(e.EMPLOYEE_ID)按顺序获取部门,并使用ROWNUM将结果限制为第一行,如下所示:
select * from (select d.DEPARTMENT_ID, d.DEPARTMENT_NAME, count(e.EMPLOYEE_ID) cnt
from departments d inner join employees e on d.DEPARTMENT_ID = e.DEPARTMENT_ID
group by d.DEPARTMENT_ID, d.DEPARTMENT_NAME order by 3 desc) where ROWNUM=1
坦率地说,我无法针对Oracle DB测试此查询,因为我的机器上只安装了Derby DB,而且它不支持ROWNUM伪插入列。
答案 2 :(得分:0)
使用像
这样的ORDER BY
子句
select d.DEPARTMENT_ID, d.DEPARTMENT_NAME,
count(e.EMPLOYEE_ID) as employe_count
from departments d
inner join employees e
on d.DEPARTMENT_ID = e.DEPARTMENT_ID
group by d.DEPARTMENT_ID, d.DEPARTMENT_NAME
order by count(e.EMPLOYEE_ID) desc
offset 0 rows fetch next 1 rows only;
注意:OFFSET
和FETCH NEXT
仅在Oracle 12.1
答案 3 :(得分:0)
您可以使用 COUNT()OVER()分析函数。
例如,使用employees
架构中的标准HR
表:
SQL> SELECT DISTINCT department_id,
2 COUNT(department_id) OVER(PARTITION BY department_id) rn
3 FROM hr.employees t
4 ORDER BY rn DESC;
DEPARTMENT_ID RN
------------- ----------
50 45
80 34
30 6
100 6
60 5
90 3
20 2
110 2
10 1
40 1
70 1
0
12 rows selected.
SQL>
从上面的结果集中找到<{1>} 最高员工:
department_id
答案 4 :(得分:0)
请查询查询:
SELECT *
FROM
(
SELECT d.DEPARTMENT_ID, d.DEPARTMENT_NAME ,COUNT(e.EMPLOYEE_ID) EMP_COUNT
FROM HR.departments d
INNER JOIN HR.employees e
ON d.DEPARTMENT_ID = e.DEPARTMENT_ID
GROUP BY d.DEPARTMENT_ID, d.DEPARTMENT_NAME
ORDER BY EMP_COUNT DESC
)
WHERE ROWNUM=1
答案 5 :(得分:0)
select dname,deptno,loc from dept where deptno=(select deptno from
(select deptno,count(*) as emp_count from emp group by deptno order by emp_count desc) where rownum=1)