Question

鉴于以下推文：

Brick Brewing Co Limited (BRB) Downgraded by Cormark to Market Perform

Brinker International Inc (EAT) Upgraded by Zacks Investment Research to Hold

如何编写删除"by Cormark"和"by Zacks Investment Research"

的正则表达式

我试过了：

"by ([A-Za-z ]+\w to)"

使用python但它需要单词“to”。我希望正则表达式在捕获“to”之前停止。

如果有人能告诉我如何编写捕获驼峰案例的正则表达式，如"Zacks Investment Research"，那也很有趣。

Answer 1

您可以使用positive look-ahead排除单词to：

>>> s1 = "Brick Brewing Co Limited (BRB) Downgraded by Cormark to Market Perform"
>>> 
>>> s2 = "Brinker International Inc (EAT) Upgraded by Zacks Investment Research to Hold"
>>> 
>>> import re
>>> re.sub(r'by[\w\s]+(?=to)','',s1)
'Brick Brewing Co Limited (BRB) Downgraded to Market Perform'
>>> re.sub(r'by[\w\s]+(?=to)','',s2)
'Brinker International Inc (EAT) Upgraded to Hold'
>>>

请注意，正则表达式[\w\s]+将匹配单词字符和空格的任意组合。如果您只想匹配字母字符和空格，可以使用[a-z\s] re.I标记（忽略大小写）。

Answer 2

要删除by之后的所有大写单词，您可以使用

by [A-Z][a-z]*(?: +[A-Z][a-z]*)*

请参阅regex demo

解释：

by - 包含3个字符b，y和空格的文字序列
[A-Z][a-z]* - 大写单词（一个大写后跟零个或多个小写字母）
(?: +[A-Z][a-z]*)* - 零个或多个序列......
- +[A-Z][a-z]* - 一个或多个空格后跟一个大写字母，后跟零个或多个小写字母。

可以在模式中用\s替换常规空间以匹配任何空格。另外，要匹配CaMeL字词，您可以将所有[a-z]替换为[a-zA-Z]。

Answer 3

您也可以使用str方法index执行此操作，然后切片并添加：

>>> def remove_name(s):
        b = s.index(' by ')
        t = s.index(' to ')
        s = s[:b]+s[t:]
        return s
>>> 
>>> s = 'Brick Brewing Co Limited (BRB) Downgraded by Cormark to Market Perform'
>>> remove_name(s)
'Brick Brewing Co Limited (BRB) Downgraded to Market Perform'
>>> 
>>> s = "Brinker International Inc (EAT) Upgraded by Zacks Investment Research to Hold"
>>> remove_name(s)
'Brinker International Inc (EAT) Upgraded to Hold'

用于删除实体名称的正则表达式

3 个答案: