Question

我有UserScores表，其数据如下：

Id    userId   Score
1       1       10
2       2       5
3       1       5

我想有一个查询或SQL块可以给我以下输出

Id    userId   Score
3       1       5
2       2       5

也就是说，我想选择属于最高'id'列值的'user id'唯一的行。

Answer 1

另一种适用于SQL Server 2000的解决方案（与上面的INNER JOIN相同，但速度稍快）是：

SELECT id, userId, Score
  FROM UserScores
 WHERE id in (SELECT MAX(id)
                FROM UserScores
               GROUP BY userId
             ) 
 ORDER BY userId

Answer 2

使用：

WITH summary AS (
    SELECT t.id,
                t.userid,
                t.score,
                ROW_NUMBER() OVER (PARTITION BY t.userid ORDER BY t.id DESC, t.score DESC) AS rank
        FROM USERSCORES sc)
SELECT s.id, 
            s.userid,
            s.score
    FROM summary s
 WHERE s.rank = 1

Answer 3

怎么样

SELECT MAX(Id), userId, Score
FROM table
GROUP BY UserId

Answer 4

SELECT U2.id, U2.userId, U2.score
FROM UserScores U2
INNER JOIN (
  SELECT U1.userId, MAX(U1.Id) MaxId
  FROM UserScores U1
  GROUP BY U1.userId
) U3
ON U2.id = U3.MaxId and U2.userId = U3.userId
ORDER BY U2.userId

如何查询其中一列具有相同值的行中具有最高列值的行

4 个答案: