Question

想要将文件备份到不同的目录。

由于文件备份非常好，但是当程序遇到文件夹时会出现错误：

Traceback (most recent call last):   
  File "C:/Users/kemburaj.kemburaj-PC/Desktop/backup.py", line 16, in   <module>
     fhand = open(file,'wb') 
FileNotFoundError: [Errno 2] No such file or directory: 'C:\\Users\\kemburaj.kemburaj-PC\\Documents\\backup\\a\\Appointment Reciept.pdf'

我的代码是：

import os

for dirname, dirs, filename in os.walk("."):
    for file in filename:
        thefile = os.path.join(dirname,file)
        source = open(thefile,'rb')
        data = source.read()
        source.close()
        Newpath = "C:\\Users\kemburaj.kemburaj-PC\Documents\\backup\\" #paste the backup directory path, please check escape characters
        if not os.path.exists(Newpath):
            os.makedirs(Newpath)
        file = os.path.join(Newpath,thefile[2:]) #copy this py file in the directory which is to be backed up
        print(file)
        fhand = open(file,'wb')
        fhand.write(data)
        fhand.close()
        print("\n\nBackup >",file)

Answer 1

请改用shutil.copytree()。类似的东西：

shutil.copytree('.', Newpath)

会做的。

Answer 2

看起来像这样：

file = os.path.join(Newpath,thefile[2:])

返回包含尚未创建的子目录名a的路径。

这是在stacktrace中返回的有问题的路径：

C:\Users\kemburaj.kemburaj-PC\Documents\backup\a\Appointment Reciept.pdf

FileNotFoundError：创建新文件时

2 个答案: