Question

我需要在{}中对Dictionary进行回复，但是他们以[]形式给出。请帮忙。这是我的代码

 func getRequestObject() -> Dictionary<String,AnyObject> {
        var requestObject = Dictionary<String,AnyObject>()
        requestObject["username"] = "a"
        requestObject["password"] = "a"
        return requestObject
    }

他们给我回复

["password": a, "username": a]

但我需要回复

{"password": a, "username": a}

Answer 1

你必须像这样将你的词典转换为json formate：

do
{
        let jsonData = try NSJSONSerialization.dataWithJSONObject(someDict, options: NSJSONWritingOptions(rawValue:0))

        let jsonString = NSString(data: jsonData, encoding: NSUTF8StringEncoding)! as String

        print(jsonString)
    }
    catch let error as NSError {
        print("Could not fetch \(error), \(error.userInfo)")
    }

Answer 2

检查一下：

    if let jsonData = try? NSJSONSerialization.dataWithJSONObject(getRequestObject(), options: [])
    {
        let jsonString = NSString(data: jsonData, encoding: NSUTF8StringEncoding)! as String

        print(jsonString)
    }

输出

{"password": "a", "username": "a"}

＆＃34; a＆＃34;是因为类型是字符串。如果您不需要报价，请尝试另一种快速替代方法，如下所示：

    var myString = getRequestObject().description
    let myRange = myString.startIndex..<myString.startIndex.advancedBy(1)
    myString.replaceRange(myRange, with: "{")
    let myRange2 = myString.endIndex.advancedBy(-1)..<myString.endIndex
    myString.replaceRange(myRange2, with: "}")
    print(myString)

Answer 3

Swift标准库中的字典具有以下语法：

let dict = [key : value, key : value, ...]

// in your case probably
let dict = getRequestObject()

打印或将其转换为String会产生相同的格式：[...]

对于带花括号的格式，您可以将字典强制转换为NSDictionary

let dict2 = dict as NSDictionary

// both result in "{key : value, key : value, ...}"
String(dict2)
print(dict2)

Answer 4

您希望字典description使用{}代替[]吗？这很简单，只需要一些字符串操作即可完成工作！

我们需要将字符串的第一个和最后一个char设置为“{”和“}”。那么让我们写一个setChar函数：

func setChar (at index: Int, _ str: String, to ch: Character) -> String {
    var charArr = Array(str.characters)
    charArr[index] = ch
    var finalString = ""
    for c in charArr {
        finalString += String(c)
    }
    return finalString
}

我只是将字符拆分成一个数组，设置字符，然后再将它们连接在一起并返回。

现在你可以先得到字典的描述：

var description = getRequestObject().description

然后调用函数：

description = setChar(at: 0, description, to: "{")
description = setChar(at: description.characters.count - 1, description, to: "}")

和BOOM！你会看到预期的结果！

您甚至可以将setChar功能扩展为String！

extension String {
    func setChar (at index: Int, to ch: Character) -> String {
        var charArr = Array(self.characters)
        charArr[index] = ch
        var finalString = ""
        for c in charArr {
            finalString += String(c)
        }
        return finalString
    }
}

Swift中的字典没有给出正确的响应

4 个答案: