我正在尝试创建一个带有关联(天气)的记录(位置)(使用外键插入)以及我尝试的每一种方式我在外键字段中以NULL值结束 weatherId
我在帮助中看到了同时创建主要和辅助实体的示例,但在这种情况下,我已预加载了Weather表,用户只能从选择列表中选择一个项目。
我发现了类似的问题,但没有人回答这个问题。
Sequelize [节点:4.2.2,CLI:2.2.1,ORM:2.0.0-rc1,mysql:^ 2.10.0]
我的模特是: -
'use strict';
module.exports = function(sequelize, DataTypes) {
var Location = sequelize.define('Location', {
id: DataTypes.INTEGER,
locationName: DataTypes.STRING
}, {
classMethods: {
associate: function(models) {
Location.hasMany(models.Rig);
Location.belongsTo(models.Weather);
}
},
freezeTableName: true,
tableName: 'Location',
timestamps: true
});
return Location;
};
mysql> desc Location;
+--------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| locationName | varchar(255) | YES | | NULL | |
| weatherId | int(11) | YES | | NULL | |
| createdAt | datetime | NO | | NULL | |
| updatedAt | datetime | NO | | NULL | |
+--------------+--------------+------+-----+---------+----------------+
'use strict';
module.exports = function(sequelize, DataTypes) {
var Weather = sequelize.define('Weather', {
id: DataTypes.INTEGER,
weatherDescription: DataTypes.STRING
}, {
classMethods: {
associate: function(models) {
Weather.hasMany(models.Location);
}
},
freezeTableName: true,
tableName: 'Weather',
timestamps: true
});
return Weather;
};
mysql> desc Weather;
+--------------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| weatherDescription | varchar(255) | YES | | NULL | |
| createdAt | datetime | NO | | NULL | |
| updatedAt | datetime | NO | | NULL | |
+--------------------+--------------+------+-----+---------+----------------+
第一次失败, NULL weatherId
models.Location.create({
locationName: locationName,
weatherId: weatherId
}).then(function(location) {
res.redirect('/location');
}).catch(function(reason) {
console.log(reason);
});
第二次尝试失败, NULL weatherId
models.Location.create({
locationName: locationName
}).then(function(location) {
models.Weather.find({where: { id: weatherId } }).then(function(weather) {
location.setWeather([weather]).then(function(location) {
res.redirect('/location');
}).catch(function(reason) {
console.log(reason);
});
}).catch(function(reason) {
console.log(reason);
});
}).catch(function(reason) {
console.log(reason);
});
然而,当我进行更新时,这有效: -
models.Location.find({
where: {
id: locationId
}
}).then(function(location) {
if (location) {
location.setWeather([weatherId]).then(function(location) {
location.updateAttributes({
locationName: locationName
}).success(function() {
res.redirect('/location');
});
});
}
}).catch(function(reason) {
console.log(reason);
res.send(reason);
})
日志中没有错误,但仍然 weatherId NULL 。
日志中的SQL不包含 weatherId ,具体如下: -
INSERT INTO `Location` (`id`,`locationName`,`createdAt`,`updatedAt`) VALUES (NULL,'test me','2016-01-04 02:33:04','2016-01-04 02:33:04');
任何人都可以帮助我,花了这么多时间在这上面......
彼得
答案 0 :(得分:1)
此问题已在https://github.com/sequelize/sequelize/issues/5138
解决按要求跑了 的console.log(Object.keys(location.rawAttributes));
得到了 [' id',' locationName',' createdAt',' updatedAt',' WeatherId' ]
表格中的 weatherId 在模型中是 WeatherId 。
它有效。