Question

我是Python的新手，我真的很想知道为什么会出现这个错误。

在尝试执行第二个findLargest循环时，我的for函数中会发生这种情况。问题是第二个for循环与第一个循环基本相同，但出于某种原因，当我尝试调用(class)method时出现错误。怎么会这样？我不允许在同一个函数中为同一个迭代创建2个for循环吗？

shapeArea=shape.area()

投掷：

TypeError: 'float' object is not callable

findlargest()的目标是循环遍历类的集合两次，首先是为了找到最大的value(Area)，而第二个尝试查找是否有其他值相等。

class Shape(object):

    def area(self):
        raise AttributeException("Subclasses should override this method.")


class Triangle(Shape):
    def __init__(self, base, height):
        self.base = base
        self.height = height
    def area(self):
        self.area = (self.base * self.height) / 2
        return self.area
    def __str__(self):
        return "{} with base {} and height {}".format(self.__class__.__name__, self.base, self.height)
    def __eq__(self, other):
        return type(other) == Triangle and self.base == other.base and self.height == other.height

class ShapeSet:

    def __init__(self):
        self.shape_list = []

    def addShape(self, sh):

        if sh not in self.shape_list:
            self.shape_list.append(sh)

        else:
            print ("{} is already existing".format(sh.__str__())) 

    def __iter__(self):
        return (self.shape_list)     

    def __str__(self):
        s = ''
        for shape in self.__iter__():
            s+= shape.__str__() + "\n"
        return s

ss = ShapeSet()
ss.addShape(Triangle(1.2,2.5))
ss.addShape(Triangle(1.4,2.5))
ss.addShape(Triangle(1.3,2.5))
ss.addShape(Triangle(1.5,2.5))

def findLargest(shapes):
    maxs = None
    maxA = 0.0
    for shape in shapes.__iter__():
        shapeArea = shape.area()
        if shapeArea > maxA or maxs == None:
            maxs = shape
            maxA = shapeArea
    maxTuple = (maxs)
    for shape in shapes.__iter__():
        shapeArea = shape.area()

Answer 1

有了这个：

def area(self):
    self.area=(self.base*self.height)/2
    return self.area

输入方法，然后通过为其引用指定其他名称立即对其进行掩码。从那时起，self.area引用该数字，您无法再访问该方法。幸运的是，修复很容易：根本不保存引用。

def area(self):
    return self.base * self.height / 2

Python不会分隔函数/方法对象和其他对象的名称。为您要保留的任何对象使用唯一的引用名称。

Answer 2

我认为你的问题在这里：

class Triangle(Shape):
def __init__(self, base, height):
    self.base=base
    self.height=height
def area(self):
    self.area=(self.base*self.height)/2 ###################### HERE
    return self.area

如果你有

shape = Triangle(1.5,2.5)
shape.area() # returns float assigned at "HERE" to shape.area
shape.area() # try to call that float assigned in previous step at "HERE"

执行相同循环时出错

2 个答案: