我正在尝试实现一个并行运行并通过队列进行通信的两个进程池。
目标是让 writer 进程使用队列将消息传递给 reader 进程。
每个流程都在终端上打印反馈,以便获得反馈。
以下是代码:
#!/usr/bin/env python
import os
import time
import multiprocessing as mp
import Queue
def writer(queue):
pid = os.getpid()
for i in range(1,4):
msg = i
print "### writer ", pid, " -> ", msg
queue.put(msg)
time.sleep(1)
msg = 'Done'
print '### '+msg
queue.put(msg)
def reader(queue):
pid = os.getpid()
time.sleep(0.5)
while True:
print "--- reader ", pid, " -> ",
msg = queue.get()
print msg
if msg == 'Done':
break
if __name__ == "__main__":
print "Initialize the experiment PID: ", os.getpid()
mp.freeze_support()
queue = mp.Queue()
pool = mp.Pool()
pool.apply_async(writer, (queue))
pool.apply_async(reader, (queue))
pool.close()
pool.join()
我期待的输出应该是这样的:
Initialize the experiment PID: 2341
writer 2342 -> 1
reader 2343 -> 1
writer 2342 -> 2
reader 2343 -> 2
writer 2342 -> 3
reader 2343 -> 3
Done
但是我只得到了这句话:
Initialize the experiment PID: 2341
然后脚本退出。
在通过队列进行通信的池中实现两个进程的进程间通信的正确方法是什么?
答案 0 :(得分:3)
我使用mp.Manager().Queue()
作为队列,因为我们无法直接传递Queue
。尝试直接使用Queue
导致异常,但由于我们使用apply_async
而未处理。
我将您的代码更新为:
#!/usr/bin/env python
import os
import time
import multiprocessing as mp
import Queue
def writer(queue):
pid = os.getpid()
for i in range(1,4):
msg = i
print "### writer ", pid, " -> ", msg
queue.put(msg)
time.sleep(1)
msg = 'Done'
print '### '+msg
queue.put(msg)
def reader(queue):
pid = os.getpid()
time.sleep(0.5)
while True:
print "--- reader ", pid, " -> ",
msg = queue.get()
print msg
if msg == 'Done':
break
if __name__ == "__main__":
print "Initialize the experiment PID: ", os.getpid()
manager = mp.Manager()
queue = manager.Queue()
pool = mp.Pool()
pool.apply_async(writer, (queue,))
pool.apply_async(reader, (queue,))
pool.close()
pool.join()
我得到了这个输出:
Initialize the experiment PID: 46182
### writer 46210 -> 1
--- reader 46211 -> 1
### writer 46210 -> 2
--- reader 46211 -> 2
### writer 46210 -> 3
--- reader 46211 -> 3
### Done
--- reader 46211 -> Done
我相信这是你的期望。