Question

我从关系中获取数据时遇到问题。我有一个调查，我想将答案，userIds和结果保存到核心数据，并在下次启动应用程序时获取数据。它们在阵列中。如果它是结果，则每个都将转换为NSManagedObject“Wert”，转换为属性“valueInt”，如果是answer或userId，则转换为“valueString”。

extension Wert {

@NSManaged var valueInt: NSNumber?
@NSManaged var valueString: String?
}

之后它将保存在NSManagedObject“Message”上，作为答案，结果或userIds上的NSSet。

extension Message {

@NSManaged var absenderId: String?
@NSManaged var absenderName: String?
@NSManaged var datum: NSDate?
@NSManaged var gruppenId: String?
@NSManaged var image: NSData?
@NSManaged var latitude: NSNumber?
@NSManaged var longitude: NSNumber?
@NSManaged var messageId: String?
@NSManaged var question: String?
@NSManaged var sound: NSData?
@NSManaged var text: String?
@NSManaged var answers: NSSet?
@NSManaged var results: NSSet?
@NSManaged var userIDs: NSSet?
}

我认为这是有效的，因为在“addObjectsFromArray”之后AnswersSet包含了一些值。

func saveCoreData(AbsenderName: String, AbsenderID: String,  Text: String?, Image: NSData?, Datum: NSDate, Latitude: Double?, Longitude: Double?, MessageId: String, Sound: NSData?, question: String?, answers : [String]?, results : [Int]?, userIDs: [String]?) {

    let newMessage = NSEntityDescription.insertNewObjectForEntityForName("Message", inManagedObjectContext: context) as NSManagedObject
    newMessage.setValue(AbsenderID, forKey: "absenderId")
    newMessage.setValue(AbsenderName, forKey: "absenderName")
    newMessage.setValue(Text, forKey: "text")
    newMessage.setValue(Image, forKey: "image")
    newMessage.setValue(Latitude, forKey: "latitude")
    newMessage.setValue(Longitude, forKey: "longitude")
    newMessage.setValue(Datum, forKey: "datum")
    newMessage.setValue(GroupId, forKey: "gruppenId")
    newMessage.setValue(MessageId, forKey: "messageId")
    newMessage.setValue(Sound, forKey: "sound")

    if question != nil && answers != nil && results != nil && userIDs != nil {

        newMessage.setValue(question, forKey: "question")

        var AnswersArray = [NSManagedObject]()
        var ResultsArray = [NSManagedObject]()
        var userIDsArray = [NSManagedObject]()

        for var index = 0; index < answers?.count ; ++index {
        let newWert = NSEntityDescription.insertNewObjectForEntityForName("Wert", inManagedObjectContext: context) as NSManagedObject
        newWert.setValue(answers![index], forKey: "valueString")
        AnswersArray.append(newWert)
        }


        for var index = 0; index < results?.count ; ++index {
            let newWert = NSEntityDescription.insertNewObjectForEntityForName("Wert", inManagedObjectContext: context) as NSManagedObject
            newWert.setValue(results![index], forKey: "valueInt")
            ResultsArray.append(newWert)
        }

        for var index = 0; index < userIDs?.count ; ++index {
            let newWert = NSEntityDescription.insertNewObjectForEntityForName("Wert", inManagedObjectContext: context) as NSManagedObject
            newWert.setValue(userIDs![index], forKey: "valueString")
            userIDsArray.append(newWert)
        }



        let answersSet = newMessage.mutableSetValueForKey("answers")
        let resultsSet = newMessage.mutableSetValueForKey("results")
        let userIdsSet = newMessage.mutableSetValueForKey("userIDs")

        answersSet.addObjectsFromArray(AnswersArray)
        resultsSet.addObjectsFromArray(ResultsArray)
        userIdsSet.addObjectsFromArray(userIDsArray)


    }



    do {
       try context.save()

    }
    catch _ {

        print("Error")
    }

}

但是当我尝试使用mutableSetValueForKey（）获取保存的值时，它们包含0个对象。其他一切都在发挥作用。

func loadCoreData() -> Int {

    var x : [AnyObject] = [AnyObject]()

    let request = NSFetchRequest(entityName: "Message")
    request.resultType = NSFetchRequestResultType.DictionaryResultType
    request.predicate = NSPredicate(format: "gruppenId = %@", GroupId)
    let sort1 = NSSortDescriptor(key: "datum", ascending: true)
    request.sortDescriptors = [sort1]



    do {

        x = try context.executeFetchRequest(request)

            for (var i = 0 ; i < x.count; ++i ) {




                let Absender = x[i].valueForKey("absenderName") as! String
                let AbsenderID = x[i].valueForKey("absenderId") as! String
                let Text : String? = x[i].valueForKey("text") as? String
                let Image : NSData? = x[i].valueForKey("image") as? NSData

                let Sound : NSData? = x[i].valueForKey("sound") as? NSData

                let Date : NSDate = x[i].valueForKey("datum") as! NSDate
                let GruppenID : String = x[i].valueForKey("gruppenId") as! String
                let MessageID : String = x[i].valueForKey("messageId") as! String

                let longitude : Double? = x[i].valueForKey("longitude") as? Double
                let latitude : Double? = x[i].valueForKey("latitude") as? Double

                let question : String? = x[i].valueForKey("question") as? String
               let answers = x[i].mutableSetValueForKey("answers") as? NSMutableSet
                let results = x[i].mutableSetValueForKey("results") as? NSMutableSet
                let userIds = x[i].mutableSetValueForKey("userIDs") as? NSMutableSet

   }
   }
   }

Answer 1

似乎答案，结果等是一对多的关系。在这种情况下，简单地设置一对一关系总是更安全（也更简洁）。

因此，您可以简单地使用反向关系，而不是维护一个笨拙的数组并处理mutableSetValueForKey：

newWert.message = newMessage

注意：请采用使用lowerCase变量名称的约定，以避免与类名混淆。

NB2：我强烈建议使用NSManagedObject子类并使用dot.notation来设置和获取值。只需一个笔划，您在上面的许多代码行中定义的所有变量都将变得完全多余。

核心数据获取关系无效

1 个答案: