颠倒传奇的顺序

时间:2016-01-03 11:34:42

标签: python matplotlib reverse legend

我使用以下代码绘制条形图。需要以相反的顺序呈现图例。我该怎么办?

colorsArr = plt.cm.BuPu(np.linspace(0, 0.5, len(C2)))
p = numpy.empty(len(C2), dtype=object)
plt.figure(figsize=(11,11))

prevBar = 0
for index in range(len(C2)):
    plt.bar(ind, C2[index], width, bottom=prevBar, color=colorsArr[index], 
            label=C0[index])
    prevBar = prevBar + C2[index]

# positions of the x-axis ticks (center of the bars as bar labels)
tick_pos = [i+(width/2) for i in ind]

plt.ylabel('Home Category')
plt.title('Affinity - Retail Details(Home category)')
# set the x ticks with names
plt.xticks(tick_pos, C1)
plt.yticks(np.arange(0,70000,3000))
plt.legend(title="Line", loc='upper left' )
# Set a buffer around the edge
plt.xlim(-width*2, width*2)
plt.show()

4 个答案:

答案 0 :(得分:33)

你可以打电话

handles, labels = ax.get_legend_handles_labels()
ax.legend(handles[::-1], labels[::-1], title='Line', loc='upper left')
import numpy as np
import matplotlib.pyplot as plt
np.random.seed(2016)

C0 = list('ABCDEF')
C2 = np.random.randint(20000, size=(len(C0), 3))
width = 1.0
C1 = ['foo', 'bar', 'baz']
ind = np.linspace(-width, width, len(C1))


colorsArr = plt.cm.BuPu(np.linspace(0, 0.5, len(C2)))
fig = plt.figure(figsize=(11,11))
ax = fig.add_subplot(1, 1, 1)

prevBar = 0
for height, color, label in zip(C2, colorsArr, C0):
    h = ax.bar(ind, height, width, bottom=prevBar, color=color, label=label)
    prevBar = prevBar + height

plt.ylabel('Home Category')
plt.title('Affinity - Retail Details(Home category)')

# positions of the x-axis ticks (center of the bars as bar labels)
tick_pos = [i+(width/2.0) for i in ind]
# set the x ticks with names
plt.xticks(tick_pos, C1)
plt.yticks(np.arange(0,70000,3000))

handles, labels = ax.get_legend_handles_labels()
ax.legend(handles[::-1], labels[::-1], title='Line', loc='upper left')

plt.show()

enter image description here

答案 1 :(得分:3)

我没有对此进行测试,因为我没有您的数据,但这是基于controlling legend entries上的文档。

handles = []
for index in range(len(C2)):
    h = plt.bar(ind, C2[index], width, bottom=prevBar, color=colorsArr[index], label=C0[index])
    handles.append(h)
    prevBar = prevBar + C2[index]

plt.legend(title="Line", loc='upper left', handles=handles[::-1])

答案 2 :(得分:3)

或者您可以使用更简单的

handles, labels = ax.get_legend_handles_labels()
ax.legend(reversed(handles), reversed(labels), title='Line', loc='upper left')

答案 3 :(得分:1)

Use a negative number for the legend vertical spacing, like this:

declare @table table (ID int, StartDate date, EndDate date)
Insert Into @table
(
    ID
    , StartDate
    , EndDate
)
Values
(1,     '2017-01-01',    '2017-02-01'),
(1,     '2017-01-09',    '2017-01-28'),
(1,     '2017-04-01',    '2017-04-30'),
(1,     '2017-04-05',    '2017-05-20'),
(1,     '2017-04-20',    '2017-06-12'),
(2,     '2017-06-02',    '2017-06-20'),
(2,     '2017-06-14',    '2017-07-31'),
(2,     '2017-06-14',    '2017-07-31'),
(2,     '2017-06-19',    '2017-07-31'),
(2,     '2017-06-19',    '2017-07-31')


;with cte as(
select
    t1.ID
    ,t1.StartDate
    ,t1.EndDate
    ,DT = (select min(StartDate) from @table t2  where t2.StartDate > DATEADD(day,30,t1.StartDate))
from
    @table t1),

cte2 as(
select
    ID
    ,StartDate
    ,EndDate
    ,dense_rank() over (order by isnull(DT,(select max(StartDate) from cte))) as Flag
from
    cte)

select 
    ID
    ,StartDate
    ,EndDate
    ,case when Flag % 2 = 0 then 2 else Flag % 2 end as Flag
from cte2

Stacked Area Chart with reversed legend

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