Question

我已经分配了一个功课，将tkinter GUI添加到普通的python代码中。
这是我的代码：

from tkinter import *
Window = Tk()
PasswordActual = Entry(Window)
Password = str(PasswordActual)
L1 = Label(Window, text = "Enter password:")
L2 = Label(Window)
def Main():
    PasswordCheck1 = len(Password)
    NumbersList = []
    CapsList = []
    LowersList = []
    def PasswordProcesser(WhatCharacters, CharactersInPassword):
        for Characters in WhatCharacters:
            if Characters in Password:
                PasswordCheck2 = Characters in Password
                if CharactersInPassword == "Numbers":
                    NumbersList.append(PasswordCheck2)
                elif CharactersInPassword == "Caps":
                    CapsList.append(PasswordCheck2)
                elif CharactersInPassword == "Lowers":
                    LowersList.append(PasswordCheck2)
    if PasswordCheck1 >= 6 and PasswordCheck1 <= 12:
        PasswordProcesser(["1","2","3","4","5","6","7","8","9"], "Numbers")
        PasswordProcesser(["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","Q","Y","Z"], "Caps")
        PasswordProcesser(["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"], "Lowers")
        NumbersInPassword = sum(NumbersList) 
        CapsInPassword = sum(CapsList)
        LowersInPassword = sum(LowersList)
        if NumbersInPassword == 0 and CapsInPassword == 0 and LowersInPassword > 0 or CapsInPassword == 0 and NumbersInPassword > 0 and LowersInPassword == 0 or LowersInPassword == 0 and CapsInPassword > 0 and NumbersInPassword == 0:
            L2.configure(text = "Password is weak")
        elif NumbersInPassword == 0 and CapsInPassword > 0 and LowersInPassword > 0 or CapsInPassword == 0 and LowersInPassword > 0 and NumbersInPassword > 0 or LowersInPassword == 0 and NumbersInPassword > 0 and CapsInPassword > 0:
            L2.configure(text = "Password is medium")
        else:
            L2.configure(text = "Password is strong")
    else:
        L2.configure(text = "Password too long or short")
Checker = Button(Window, text = "Check Password", command = Main)
L1.grid(row = 1, column = 1)
PasswordActual.grid(row = 1, column = 2)
Checker.grid(row = 2, column = 1)
L2.grid(row = 2, column = 2)

我想要的输出告诉用户他或她的代码是弱，中等或强。它没有添加tkinter的东西，但它反复告诉我，我的密码很弱。这有什么理由，还是我只是愚蠢？（我是tkinter初学者）Thx提前。
这是我没有GUI的（工作）代码：

def Main2():
    Password = input("What is your password?: ") 
    PasswordCheck1 = len(Password)
    NumbersList = []
    CapsList = []
    LowersList = []
    def ExitFunc():
        Exit = input("Do you want to exit or retry?: ")
        if Exit == "exit" or Exit == "Exit":
            exit
        elif Exit == "retry" or Exit == "Retry":
            Main2()
        else:
            print("Invalid input, enter exit or retry")
            ExitFunc()
    def PasswordProcesser(WhatCharacters, CharactersInPassword):
        for Characters in WhatCharacters:
            if Characters in Password:
                PasswordCheck2 = Characters in Password
                if CharactersInPassword == "Numbers":
                    NumbersList.append(PasswordCheck2)
                elif CharactersInPassword == "Caps":
                    CapsList.append(PasswordCheck2)
                elif CharactersInPassword == "Lowers":
                    LowersList.append(PasswordCheck2)
    if PasswordCheck1 >= 6 and PasswordCheck1 <= 12:
        PasswordProcesser(["1","2","3","4","5","6","7","8","9"], "Numbers")
        PasswordProcesser(["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","Q","Y","Z"], "Caps")
        PasswordProcesser(["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"], "Lowers")
        NumbersInPassword = sum(NumbersList)
        CapsInPassword = sum(CapsList)
        LowersInPassword = sum(LowersList)
        if NumbersInPassword == 0 and CapsInPassword == 0 and LowersInPassword > 0 or CapsInPassword == 0 and NumbersInPassword > 0 and LowersInPassword == 0 or LowersInPassword == 0 and CapsInPassword > 0 and NumbersInPassword == 0:
            print("Password is weak, try and include capital, lowercase and numerical characters")
            ExitFunc()
        elif NumbersInPassword == 0 and CapsInPassword > 0 and LowersInPassword > 0 or CapsInPassword == 0 and LowersInPassword > 0 and NumbersInPassword > 0 or LowersInPassword == 0 and NumbersInPassword > 0 and CapsInPassword > 0:
            print("Password is medium, try and include capital, lowercase and numerical characters")
            ExitFunc()
        else:
            print("Password is strong")
            ExitFunc()
    else:
        print("Password too long or short, it needs to be no shorter than 6 and no longer than 12")
        ExitFunc()
Main2()

Answer 1

问题在于密码获取。
您应该在Entry函数中Main获取密码，如下所示：

PasswordCheck1 = len(PasswordActual.get())

有必要删除第三行Password = str(PasswordActual)，因为它是对PasswordActual的引用。

看看这个：

from tkinter import *
Window = Tk()
PasswordActual = Entry(Window)
L1 = Label(Window, text = "Enter password:")
L2 = Label(Window)
def Main():
    Password = PasswordActual.get()
    PasswordCheck1 = len(Password)
    ..............................

Python tkinter问题

1 个答案: