Question

这是我的XML文件：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<dragonDatabase xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <dragon>
        <Name>Hackatoo</Name>
        <Description>This impulsive and reckless member of the Sharp Class is a master at collecting wood...so long as its axe-like snout doesn't get stuck in the tree its cutting! Hackatoo eggs laid at a high altitude can hook on to whatever they hit.</Description>
        <Class>Sharp</Class>
        <Fire-Type>No Data</Fire-Type>
        <Diet>No Data</Diet>
    </dragon>
    <dragon>
        <Name>Hobblegrunt</Name>
        <Description>The Hobblegrunt has a single horn and and an expandable frill surrounding its head. It has clawed wings, small arms and big legs like a Deadly Nadder. It also appears to have long neck and tail as well. The Hobblegrunt doesn't have a particular color, but instead it changes color depending on its mood.</Description>
        <Class>Stoker, Boulder</Class>
        <Fire-Type>Ethane Expectorant</Fire-Type>
        <Diet>No Data</Diet>
    </dragon>
</dragonDatabase>

这是我的DragonBean类：

public class DragonBean {
    private String name;
    private String description;
    private String dragonClass;
    private String fireType;
    private String diet;



    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public String getDescription() {
        return description;
    }
    public void setDescription(String description) {
        this.description = description;
    }
    public String getDragonClass() {
        return dragonClass;
    }
    public void setDragonClass(String dragonClass) {
        this.dragonClass = dragonClass;
    }
    public String getFireType() {
        return fireType;
    }
    public void setFireType(String fireType) {
        this.fireType = fireType;
    }
    public String getDiet() {
        return diet;
    }
    public void setDiet(String diet) {
        this.diet = diet;
    }

}

基本上我想在xml中获取每个龙并将其放在包含DragonBean类型的列表中。我知道我必须解析XML。但我不知道从哪里开始。将信息放入列表后，我计划使用Jackson将其转换为JSON文件。

Answer 1

使用DocumentBuilderFactory和DocumentBuilder类，解析xml文件。首先获取龙的节点列表，然后逐个迭代它。在每次迭代中获取子节点，然后读取获取这些标记的文本内容并设置模型类。将工作。希望它有所帮助！

如何将此xml中的相应标记放置到java对象中

1 个答案: