Question

从php脚本中检索以下JSON数据，现在我想解析这个JSON数据。请有人帮我解析这个JSON数据。

[{
    "0": "1.0000",
    "AVG(Q1)": "1.0000",
    "1": "1.8000",
    "AVG(Q2)": "1.8000",
    "2": "2.0000",
    "AVG(Q3)": "2.0000",
    "3": "2.4000",
    "AVG(Q4)": "2.4000",
    "4": "1.6000",
    "AVG(Q5)": "1.6000",
    "5": "1.2000",
    "AVG(Q6)": "1.2000",
    "6": "2.0000",
    "AVG(Q7)": "2.0000",
    "7": "2.4000",
    "AVG(Q8)": "2.4000",
    "8": "0.8000",
    "AVG(Q9)": "0.8000",
    "9": "2.8000",
    "AVG(Q10)": "2.8000",
    "10": "1.8000",
    "AVG(Q11)": "1.8000"
}, {
    "0": null,
    "AVG(Q1)": null,
    "1": null,
    "AVG(Q2)": null,
    "2": null,
    "AVG(Q3)": null,
    "3": null,
    "AVG(Q4)": null,
    "4": null,
    "AVG(Q5)": null,
    "5": null,
    "AVG(Q6)": null,
    "6": null,
    "AVG(Q7)": null,
    "7": null,
    "AVG(Q8)": null,
    "8": null,
    "AVG(Q9)": null,
    "9": null,
    "AVG(Q10)": null,
    "10": null,
    "AVG(Q11)": null
}]

我尝试了不同的方法来解析这个JSON，但所有方法都失败了。请帮我解析一下这个JSON。

我尝试了这个但是表格元素中没有显示任何值：

var obj = jQuery.parseJSON(data);
$.each(obj, function(key, value){          
    $('table').append('<tr><td>'+value.avg(q1)+'</td></tr>');
});

Answer 1

请检查代码段。无需解析json。

var jsobObj = [{
    "0": "1.0000",
    "AVG(Q1)": "1.0000",
    "1": "1.8000",
    "AVG(Q2)": "1.8000",
    "2": "2.0000",
    "AVG(Q3)": "2.0000",
    "3": "2.4000",
    "AVG(Q4)": "2.4000",
    "4": "1.6000",
    "AVG(Q5)": "1.6000",
    "5": "1.2000",
    "AVG(Q6)": "1.2000",
    "6": "2.0000",
    "AVG(Q7)": "2.0000",
    "7": "2.4000",
    "AVG(Q8)": "2.4000",
    "8": "0.8000",
    "AVG(Q9)": "0.8000",
    "9": "2.8000",
    "AVG(Q10)": "2.8000",
    "10": "1.8000",
    "AVG(Q11)": "1.8000"
}, {
    "0": null,
    "AVG(Q1)": null,
    "1": null,
    "AVG(Q2)": null,
    "2": null,
    "AVG(Q3)": null,
    "3": null,
    "AVG(Q4)": null,
    "4": null,
    "AVG(Q5)": null,
    "5": null,
    "AVG(Q6)": null,
    "6": null,
    "AVG(Q7)": null,
    "7": null,
    "AVG(Q8)": null,
    "8": null,
    "AVG(Q9)": null,
    "9": null,
    "AVG(Q10)": null,
    "10": null,
    "AVG(Q11)": null
}];


$.each(jsobObj, function(key, value){          
    $('table').append('<tr><td>'+(value["AVG(Q1)"]==null?"":value["AVG(Q1)"])+'</td></tr>');
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
  </table>

如何在jquery ajax成功函数中解析json

1 个答案: