Question

我在Spring + Hibernate MVC项目中执行CRUD时出错，IDE返回HTTP Status 400错误。我检查了一些链接，但它们不是解决方案：

The request sent by the client was syntactically incorrect.-Spring MVC + JDBC Template
Spring: The request sent by the client was syntactically incorrect ()
http://www.coderanch.com/t/643301/Spring/Spring-MVC-request-message-request

以下是我的jsp页面中的表单：

<form:form action="quantity.do" method="GET" commandName="quantity">
                <form:input type="hidden" path="quantityId" value="1"/>
                <form:input type="hidden" path="clothes" value="<%= clothe%>"/>
                <div style="height: 35px; width: 20%; float: left;">
                    Choose color:
                </div>
                <div style="height: 35px; width: 78%; float: left">
                    <form:select path="color">
                        <!--object Color-->
                        <form:option value="" label=" - choose color - "/>
                        <form:options items="${colors}" itemLabel="name"/>
                    </form:select>
                </div>
                <div style="height: 35px; width: 20%; float: left;">
                    Choose Size
                </div>
                <div style="height: 35px; width: 78%; float: left;">
                    <form:select path="size">
                        <!--object size-->
                        <form:option value="" label=" - choose size - "/>
                        <form:options items="${sizes}" itemLabel="sizeDescription"/>
                    </form:select>
                </div>
                <div style="height: 35px; width: 20%; float: left;">
                    Quantity:
                </div>
                <div style="height: 35px; width: 78%; float: left;">
                    <form:input type="number" path="quantityOfClothes"/>
                </div>
                <div style="width: 100%; height: 25px"></div>
                <div style="height: 50px; width: 16%; float: left; margin-left: 50px">
                    <input type="submit" name="action" value="Add"/>
                </div>
                <div style="height: 50px; width: 16%; float: left; margin-left: 50px">
                    <input type="submit" name="action" value="Update"/>
                </div>
                <div style="height: 50px; width: 16%; float: left; margin-left: 50px">
                    <input type="submit" name="action" value="Cancel"/>
                </div>
            </form:form>

这是控制器：

@RequestMapping(value = "/quantity.do", method = RequestMethod.GET)
public String doActions(@ModelAttribute Quantity quantity, @RequestParam String action, Map<String, Object> map) {

    switch (action.toLowerCase()) {
        case "add":
            break;
        case "update":
            break;
        case "cancel":
            break;
    }
        return "quantity";
    }

当我使用＆＃34;添加＆＃34;时，我的所有对象都是通过Serializable实现的。行动，网址将显示：＆＃34; http://localhost:8080/pinky_spring/quantity.do?quantityId=1&clothes=model.Clothes@229db7d5&color=model.Color@6b248b2f&size=model.Size@591a3a57&quantityOfClothes=1000&action=Add＆＃34;有这个错误。请告诉我这里有什么问题以及如何解决这个问题，我是Java Web的新手。

更新：这是数量类

@Entity
@Table(name = "Quantity", schema = "dbo", catalog = "PinkyDB")
public class Quantity implements java.io.Serializable {

private int quantityId;
private Clothes clothes; //an object
private Color color; //an object
private Size size; //an object
private Integer quantityOfClothes;
private Set<ShoppingCart> shoppingCarts = new HashSet<ShoppingCart>(0);

public Quantity() {
}

public Quantity(int quantityId, Clothes clothes, Color color, Size size) {
    this.quantityId = quantityId;
    this.clothes = clothes;
    this.color = color;
    this.size = size;
}

public Quantity(int quantityId, Clothes clothes, Color color, Size size, Integer quantityOfClothes, Set<ShoppingCart> shoppingCarts) {
    this.quantityId = quantityId;
    this.clothes = clothes;
    this.color = color;
    this.size = size;
    this.quantityOfClothes = quantityOfClothes;
    this.shoppingCarts = shoppingCarts;
}

@Id
@Column(name = "QuantityID", unique = true, nullable = false)
public int getQuantityId() {
    return this.quantityId;
}

public void setQuantityId(int quantityId) {
    this.quantityId = quantityId;
}

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "ClothID", nullable = false)
public Clothes getClothes() {
    return this.clothes;
}

public void setClothes(Clothes clothes) {
    this.clothes = clothes;
}

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "ColorID", nullable = false)
public Color getColor() {
    return this.color;
}

public void setColor(Color color) {
    this.color = color;
}

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "SizeID", nullable = false)
public Size getSize() {
    return this.size;
}

public void setSize(Size size) {
    this.size = size;
}

@Column(name = "QuantityOfClothes")
public Integer getQuantityOfClothes() {
    return this.quantityOfClothes;
}

public void setQuantityOfClothes(Integer quantityOfClothes) {
    this.quantityOfClothes = quantityOfClothes;
}

@OneToMany(fetch = FetchType.LAZY, mappedBy = "quantity")
public Set<ShoppingCart> getShoppingCarts() {
    return this.shoppingCarts;
}

public void setShoppingCarts(Set<ShoppingCart> shoppingCarts) {
    this.shoppingCarts = shoppingCarts;
}}

Answer 1

参数“clothe”必须是基本类型，在您的情况下，clothe是一个可序列化的对象，但它不能被浏览器自动序列化。

更新：你可以这样解决：

<form:input type="hidden" path="clothes.id" value="<%=clothe.getId()%>"/>

Answer 2

如果select case when sum(quantity) = 0 then 0 else sum(unitprice * quantity) / sum(quantity) end from sales;，Clothe和Color是实体，并且您想要从数据库加载它们而不是创建新的一次，那么您需要做两件事：

1）发送表单
2）添加一个能够将ID转换为实体的Spring-Converter。

对于某些示例实现，请查看此博客“Spring ID to Entity Conversion”：

错误＆＃34;客户端发送的请求在语法上不正确＆＃34;当使用Spring MVC进行CRUD时

2 个答案: