Question

我的程序问题如下。我有多次购买的不同商品编号（订单编号）的记录。当我根据项目编号返回部分购买时，它应该从items表中删除记录并将项目详细信息插入名为`deleted_items'的表中。问题是当我删除部分订单时表一次，表deleted_Items将出现此错误：

ORA-06512：第4行 00001. 00000 - “违反了唯一约束（％s。％s）” *原因：UPDATE或INSERT语句尝试插入重复键。对于在DBMS MAC模式下配置的Trusted Oracle，您可能会看到如果重复条目存在于不同级别，则显示此消息。 *操作：删除唯一限制或不插入密钥。

  create or replace PROCEDURE RET_Item(Item_no number(5))
           AS
       CURSOR Return_i
          IS
       SELECT * FROM Items
       WHERE item_num = Item_no
       AND Item_num IN (SELECT Item_num FROM deleted_items);
     cur1 Return_i%ROWTYPE;
   BEGIN    
   OPEN Return_i;
    LOOP
     FETCH Return_i INTO cur1;
    EXIT WHEN Return_i%NOTFOUND;
     IF cur1.Delivered IS NOT NULL THEN

     Insert into deleted_itmes values(
         cur1.Order_No,cur1.Item_num,cur1.Delivered,User,sysdate,   
           'Item_returned');

     DELETE FROM Items WHERE Item_num = Item_no ;
     DELETE FROM Purchase where Item_num = Item_no;
    DBMS_OUTPUT.PUT_LINE('Item number ' || Item_no ||' deleted! ');
     ELSIF cur1.Delivered IS NULL THEN
    DBMS_OUTPUT.PUT_LINE('Cannot return item: '|| cur1.Item_num);
   END IF;
  END LOOP;
 CLOSE Return_i;
END RET_item;

项目表

         Order_No      Item_num      Delivered   
        ----------    ----------     --------- 
           1001          1234        12-JUN-15           
           1002          5678        01-JAN-15  
           1003          9087        05-FEB-15

购买表

             Order_No     Item_num     Quantity  
            ----------   ----------   --------------- 
               1001        1234           10
               1001        9087           7
               1002        9087           10 
               1003        1234           1 
               1003        5678           12

Deleted_Item表

项目表

      Order_No   Item_num    Delivered   Name_on-order  Date_of_Ret  Status

Answer 1

从您的代码中不清楚，您要插入哪个表..您可以粘贴整个INSERT语句吗？

如果要插入DELETED_ITEMS表，那么为什么需要

AND Item_num IN (SELECT Item_num FROM deleted_items)

不应该

AND Item_num NOT IN (SELECT Item_num FROM deleted_items)

违反了唯一约束（％s。％s）

1 个答案: