Question

我有以下代码：

iif

我怎样才能实现结果，Python每次通过`while-loop时都会遍历列表＆＃39; nthTime＆＃39;

我可以使用嵌套的for循环，但当然这会运行整个列表，这不是我的目标。

因此，我得出结论，我需要使用嵌套的while循环;但是我无法弄清楚确切的语法。

我希望将来这对其他人来说也是一个有用的问题。

Answer 1

仅当用户输入正确的值

时，才使用for循环并中断循环

for iteration in nthTime:
    if shape.lower() not in ["octagon","heptagon","hexagon"]:
        print("Please select a shape from the list!")
        shape = input("Pick a shape, for the " + iteration + " time! ")
    else: break
else: print "You have wasted all your chances, try again later"

Answer 2

这样的事情：

shape = input("Please enter your choice of shape? ")    

nthTime = ["second","third","fourth","fifth","sixth"]
undesired_shapes = ["octagon","heptagon","hexagon"]

indx = 0

while shape.lower() not in undesired_shapes:
    print("Please select a shape from the list!")
    shape = input("Pick a shape, for the " + nthTime[indx] + " time! ")
    indx += 1
    if indx >= len(nthTime):
        print 'Giving up !!'
        break

Answer 3

locale: 'ru'

Python：如何迭代嵌套在while循环中的列表？

3 个答案: