我正在尝试使用类模板和运算符覆盖在C ++中实现自己的集合。
我的MySet.h文件中有以下代码:
#include "stdafx.h"
#pragma once
#include <iostream>
#include <string>
using namespace std;
#define DEFAULT_LEN 10
template <class T> class MySet
{
public:
MySet(int len = DEFAULT_LEN)
{
elements = new T[len];
count = 0;
}
~MySet()
{
delete elements;
}
MySet<T> operator+(T &element)
{
cout << "Some code here!"; //deleted to simplify code, the problem is that this method is not seen in main
return MySet<T>();
}
string writeSet()
{
string result = "";
for (int i = 0;i < count; i++)
{
result += elements[i] + ", ";
}
return result;
}
private:
T* elements;
int count;
};
这是我的主要内容:
#include "stdafx.h"
#include "MySet.h"
int main()
{
MySet<int> a = MySet<int>(10);
cout << a.writeSet();
a = a + 2;
a = a + 3;
a = a + 4;
cout << a.writeSet();
return 0;
}
不幸的是,我在填写这些内容时遇到了问题:
a = a + 2;
。输出是:
1>c:\path\main.cpp(11): error C2679: binary '+': no operator found which takes a right-hand operand of type 'int' (or there is no acceptable conversion)
1> c:\path\myset.h(22): note: could be 'MySet<int> MySet<int>::operator +(T &)'
1> with
1> [
1> T=int
1> ]
这怎么可能?据我了解,由于T型,MySet<T> operator+(T &element)
应该足够了。我错过了什么?
答案 0 :(得分:4)
必须是:
MySet<T> operator+(const T &element)