Question

我尝试更新SQL表，但我的代码不起作用。也许有人可以看一下。

<?php
$servername = "localhost";
$username = "user";
$password = "pwd";
$dbname = "db";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 
$sql = "UPDATE pm_videos SET `description` = REPLACE( `description` ,  "Instagram:",  "" ";
if ($conn->query($sql) === TRUE) {
    echo "Record updated successfully";
} else {
    echo "Error updating record: " . $conn->error;
}

$conn->close();
?>

我收到500错误。

当我在数据库中直接执行它时，效果非常好：

UPDATE pm_videos 
SET `description` = REPLACE(`description`, "Instagram:",  "");

Answer 1

$which python -a
/usr/local/bin/python

您的代码中有一些语法错误尝试上面的

Answer 2

你搞砸了引号问题。这会改变

$sql = "UPDATE pm_videos SET  `description` = REPLACE(  `description` ,  'Instagram:',  '' )";

Answer 3

这是因为当您在另一个$this->email->set_mailtype("html");中包含"时，PHP假设您正在关闭语句。要解决此问题，只需在双引号内包含单引号，例如：

Answer 4

那是因为你错误地连接了字符串“Instagram”：和“”。

试试这段代码：

 $sql = 'UPDATE pm_videos SET  `description` = REPLACE(  `description` ,  "Instagram:",  ""); ';

Answer 5

请使用单引号或双引号：

$sql = "UPDATE pm_videos SET `description` = REPLACE( `description` ,  'Instagram:',  '' ";

MySQL通过PHP更新

5 个答案: