这是对此处提出的问题的跟进:Groovy parsing text file
现在的区别是我的文件有一个标题,我试图首先阅读标题,然后阅读我想要的内容,但由于某种原因它似乎没有合作。
def dataList = []
def theInfoName = 'testdata.txt'
boolean headersDone = false //header set to false by default
File theInfoFile = new File( theInfoName )
if( !theInfoFile.exists() ) {
println "File does not exist"
} else {
def driveInfo = [:]
// Step through each line in the file
theInfoFile.eachLine { line ->
//this is where im trying to account for the header
if(!headersDone) { //look if line contains "..." if it does that turn headersDone to true
if(line.contains("...")) {
headersDone = true
}
} else {
// If the line isn't blank
if( line.trim() ) {
// Split into a key and value
def (key,value) = line.split( '\t: ' ).collect { it.trim() }
// and store them in the driveInfo Map
driveInfo."$key" = value
}
else {
// If the line is blank, and we have some info
if( driveInfo ) {
// store it in the list
dataList << driveInfo
// and clear it
driveInfo = [:]
}
}
}
// when we've finished the file, store any remaining data
if( driveInfo ) {
dataList << driveInfo
}
}
dataList.eachWithIndex { it, index ->
println "Drive $index"
it.each { k, v ->
println "\t$k = $v"
}
}
我使用上一篇文章中提供的代码尝试了它,以确保它不是我做的不同而且它带有相同的输出。
它会发布11次相同的信息块。
标题看起来如下:
Random date information here with some other info
Slightly more random information followed by
Examining hard disk information ...
HDD Device 0 : /dev/sda
HDD Model ID : ST3160815A
HDD Serial No : 5RA020QY
HDD Revision : 3.AAA
HDD Size : 152628 MB
Interface : IDE/ATA
Temperature : 33 C
Health : 100%
Performance : 70%
Power on Time : 27 days, 13 hours
Est. Lifetime : more than 1000 days
HDD Device 1 : /dev/sdb
HDD Model ID : TOSHIBA MK1237GSX
HDD Serial No : 97LVF9MHS
HDD Revision : DL130M
HDD Size : 114473 MB
Interface : S-ATA
Temperature : 30 C
Health : 100%
Performance : 100%
Power on Time : 38 days, 11 hours
Est. Lifetime : more than 1000 days
有谁知道为什么打印出重复的信息?
答案 0 :(得分:2)
问题是在driveInfo
添加了“最后一个”dataList
:
// when we've finished the file, store any remaining data
if( driveInfo ) {
dataList << driveInfo
}
它必须是当前位置下方的一个大括号,否则它属于eachLine闭包。
答案 1 :(得分:0)
看不到任何明显错误的代码。我建议添加几个println
,以便您可以看到地图,列表和变量的变化情况。这可能会让你知道bug可能在哪里。