Question

我正在尝试使用ajax打印“Hello World！”，当您单击按钮时，由于某种原因它无法正常工作。我做错了什么？

test1.php

#testID {
border: 1px solid purple;
height: 50%;
width: 50%;
}

<?php

$commentID = "commentID";
$comment = "comment";

echo "
<input  type = 'submit' value = 'Post' onclick = \"ajaxPass('test2.php', $comment, $commentID,'testID')\">
<div id = 'testID'></div>
";

?>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script> 
<script type = "text/javascript"> 

function ajaxPass(action,comment,commentID,outputID) {

$.ajax({
type: "POST",
url: action,
data: { comment: comment, commentID: commentID },
error: function(xhr,status,error){alert(error);},
success:function(data) {
document.getElementById(outputID).innerHTML = data;        
} //end of success:function(data)
}); //end of $.ajax({

} //end of function ajaxPass(action,comment,commentID,outputID)

</script>

test2.php

<?php

echo "Hello World!";

?>

Answer 1

您的代码中存在语法错误。您的echo声明应该是这样的：

echo "<input  type = 'submit' value = 'Post' onclick = \"ajaxPass('post.php', '{$comment}', '{$commentID}','testID')\"><div id = 'testID'></div>";

在浏览器上使用ctrl+u查看源代码，并检查onclick属性中的内容。

并在 test1.php 页面中添加此div <div id="outputID"></div>。

使用ajax打印“Hello World！”当您单击按钮时

1 个答案: