Question

所以我想从循环中保存一个变量但是当它重新启动它时会改变变量

print('Dice script')
for i in range(3):
  print('Rolling')
  time.sleep(1)
  droll = (randint(1, 6))
  sdroll = str(droll)
  print('Dice rolled '+ sdroll)
  time.sleep(3)
add = (Here I want to add up the variables that i got from the three loops)
print(add)

这样我三次得到变量droll

Answer 1

使用列表在每次迭代中保存sdroll值，这样：

sdroll_list= []
print('Dice script')
for i in range(3):
    print('Rolling')
    time.sleep(1)
    droll = (randint(1, 6))
    sdroll = str(droll)
    sdroll_list.append(sdroll)
    print('Dice rolled '+ sdroll)
    time.sleep(3)
add_string = ' '.join(sdroll_list)) #Concatenate the strings in sdroll_list
add_values = sum(map(int, sdroll_list)) #Sum values converted from sdroll_list
print(add)

修改

如果您想sum每次迭代的droll值，请按以下步骤操作：

print('Dice script') sum_droll = 0 for i in range(3): print('Rolling') time.sleep(1) droll = (randint(1, 6)) sum_droll += droll #sum droll values sdroll = str(droll) print('Dice rolled '+ sdroll) time.sleep(3) print(sum_droll)

Answer 2

如果您需要的只是总和，并且您不需要知道个别结果是什么，您可以在循环本身中将它们相加。

sdroll_sum = 0
print('Dice script')
for i in range(3):
    print('Rolling')
    time.sleep(1)
    droll = (randint(1, 6))
    sdroll_sum += droll
    print('Dice rolled '+ str(droll))
    time.sleep(3)
print(sdroll_sum)

如何从循环中保存变量并稍后将其恢复

2 个答案: