Question

我尝试使用apache cookbook中的以下代码将默认端口80映射到443但是在运行厨师时仍然出现错误。你能就此提出建议吗？我尝试映射到＃80以外的端口，因为我的食谱中也有nginx配方，所以想设置apache2来监听diff端口 -

* apache/attribute/default.rb

default['apache']['dir']          = '/etc/apache2'
default['apache']['listen_ports'] = [ '80','443' ]

* apache/recipes/default.rb

package "apache2" do
    action :install
end

service "apache2" do
    action [:enable, :start]
end


template "/var/www/index.html" do
    source "index.html.erb"
    mode "0644"
end

Vagrant provision error -
    ================================================================================
    ==> default:     
    ==> default: Error executing action `start` on resource 'service[apache2]'
    ==> default:     
================================================================================

    ==> default:     
    ==> default: Mixlib::ShellOut::ShellCommandFailed
    ==> default:     
    ==> default: ------------------------------------
    ==> default:     
    ==> default: Expected process to exit with [0], but received '1'


This time I had used  ==> 
attribute/default.rb with below content but still getting error -
default['apache']['dir']          = '/etc/apache2'
default['apache']['listen_ports'] = [ '81’ ]

Error    
==> default: STDOUT: * Starting web server apache2
==> default: 
==> default:     Action 'start' failed.
==> default:     The Apache error log may have more information.
==> default:        ...fail!
==> default:     STDERR: apache2: Could not reliably determine the server's fully qualified domain name, using 127.0.1.1 for ServerName
==> default:     (98)Address already in use: make_sock: could not bind to address 0.0.0.0:80

Answer 1

listen_ports不是映射，它设置要侦听的端口。如果您不想听80，请不要将其包含在该阵列中。

如何在apache2 cookbook中转发端口

1 个答案: