Question

我想在存储过程中更新在字符串逗号分隔列表中传递的ID列表，其中包含以逗号分隔的字符串值列表。

那么如何使用2个列表中的相应名称更新每个ID。例如：

ids = "1, 2, 4 ,8";
names = "sam, john, sarah ,barry";

ALTER PROCEDURE [dbo].[update_work]
  @ids nvarchar(MAX),
  @names nvarchar(MAX)
AS
BEGIN
    ???
END

Answer 1

正确的方法是使用表值参数。

但是你说你不能这样我会使用SUBSTRING和tally table来分割逗号分隔的字符串。

结构：

CREATE TABLE #tab(id INT, name VARCHAR(100));

INSERT INTO #tab(id, name)
VALUES (1, 'a'), (2, 'b'), (3, 'c'), (4, 'd'),
       (5, 'e'), (6, 'f'), (7, 'g'), (8, 'h'), (9, 'i');

过程（临时过程，因为SEDE不允许创建普通的数据库对象）：

CREATE PROCEDURE #update_work @ids nvarchar(MAX), @names nvarchar(MAX)
AS
BEGIN
 ;WITH cte AS
 ( SELECT TOP 1000 rn = ROW_NUMBER() OVER(ORDER BY 1/0)
   FROM master..spt_values
 ), cte2 AS
 ( SELECT [val] = SUBSTRING(',' + @ids + ',', rn + 1,
                   CHARINDEX(',', ',' + @ids + ',', rn + 1) - rn -1)
         ,[r] =  ROW_NUMBER() OVER(ORDER BY rn)
         ,[type] = 'id'
  FROM cte
  WHERE rn <= LEN(',' + @ids + ',') - 1
   AND SUBSTRING(',' + @ids + ',', rn, 1) = ','
  UNION ALL 
  SELECT [val] = SUBSTRING(',' + @names + ',', rn + 1,
                   CHARINDEX(',', ',' + @names + ',', rn + 1) - rn -1)
         ,[r] =  ROW_NUMBER() OVER(ORDER BY rn)
         ,[type] = 'name'
  FROM cte
  WHERE rn <= LEN(',' + @names + ',') - 1
   AND SUBSTRING(',' + @names + ',', rn, 1) = ','
 ), cte3 AS
 ( SELECT [id] = cte2.val, [name] = cte2a.val
   FROM cte2
   JOIN cte2 AS cte2a
     ON cte2.[r] = cte2a.[r]
    AND cte2.[type] = 'id'
    AND cte2a.[type] = 'name'
 )
 UPDATE t
 SET name = c3.name
 FROM #tab AS t
 JOIN cte3 c3 ON t.id = c3.id;
END;

测试：

EXEC #update_work
    @ids = '1, 2, 4 ,8', 
    @names = 'sam, john, sarah ,barry';

SELECT * 
FROM #tab;

LiveDemo

输出：

╔════╦═══════╗
║ id ║ name  ║
╠════╬═══════╣
║  1 ║ sam   ║
║  2 ║ john  ║
║  3 ║ c     ║
║  4 ║ sarah ║
║  5 ║ e     ║
║  6 ║ f     ║
║  7 ║ g     ║
║  8 ║ barry ║
║  9 ║ i     ║
╚════╩═══════╝

SQL Update字符串列表，其中包含字符串值列表

1 个答案: