Question

我有九个变量和一个函数，但是我关注这个问题的变量部分。（此代码的前九行。）

groceryfruits1 = 'The number of fruit(s) in the grocery bag is: 1.'
groceryfruits2 = 'The number of fruit(s) in the grocery bag is: 2.'
groceryfruits3 = 'The number of fruit(s) in the grocery bag is: 3.'
groceryfruits4 = 'The number of fruit(s) in the grocery bag is: 4.'
groceryfruits5 = 'The number of fruit(s) in the grocery bag is: 5.'
groceryfruits6 = 'The number of fruit(s) in the grocery bag is: 6.'
groceryfruits7 = 'The number of fruit(s) in the grocery bag is: 7.'
groceryfruits8 = 'The number of fruit(s) in the grocery bag is: 8.'
groceryfruits9 = 'The number of fruit(s) in the grocery bag is: 9.'

def checkout(itemcount, category):
    if category == "fruits":
        if itemcount == 1:
            print groceryfruits1
        elif itemcount == 2:
            print groceryfruits2
        elif itemcount == 3:
            print groceryfruits3
        elif itemcount == 4:
            print groceryfruits4
        elif itemcount == 5:
            print groceryfruits5
        elif itemcount == 6:
            print groceryfruits6
        elif itemcount == 7:
            print groceryfruits7
        elif itemcount == 8:
            print groceryfruits8
        elif itemcount == 9:
            print groceryfruits9

checkout(9, "fruits")

由于存在一个连续的变量列表，并且将所有变量放在一行中会更加有序，有没有办法做到这一点？

Answer 1

您可以将代码简化为：

groceryfruits = 'The number of fruit(s) in the grocery bag is: {}.'

def checkout(itemcount, category):
    if category == "fruits":
        print groceryfruits.format(itemcount)

checkout(9, "fruits")

Answer 2

水果计数之前的字符串总是相同的，那么为什么不将它编码到你的函数中？

def checkout(itemcount, category):
    if category == 'fruits':
        print 'The number of fruit(s) in the grocery bag is: {0}.'.format(itemcount)

一旦你有更多的项目类别，你可能会考虑像这样（或类似的）编写你的函数，以允许更多的灵活性：

def item_checkout(itemcount, category):
    print 'the number of {0} items in the grocery bag is: {1}'.format(category, itemcount)

或者，如果您想要一般的结帐功能，请使用(itemcount, category)元组列表：

def total_checkout(items):
    'items: list of (itemcount, category) tuples'
    for itemcount, category in items:
        print 'the number of {0} items in the grocery bag is: {1}'.format(category, itemcount)

演示：

>>> total_checkout([(5, 'banana'), (2, 'fruit'), (7, 'sirup')])
the number of banana items in the grocery bag is: 5
the number of fruit items in the grocery bag is: 2
the number of sirup items in the grocery bag is: 7

Answer 3

通常，一组类似命名的变量应合并为一个列表。（为此，我们忽略了值本身是相似的，其他答案都是优越的。）

groceryfruits = [
    'The number of fruit(s) in the grocery bag is: 1.',
    'The number of fruit(s) in the grocery bag is: 2.',
    'The number of fruit(s) in the grocery bag is: 3.',
    'The number of fruit(s) in the grocery bag is: 4.',
    'The number of fruit(s) in the grocery bag is: 5.',
    'The number of fruit(s) in the grocery bag is: 6.',
    'The number of fruit(s) in the grocery bag is: 7.',
    'The number of fruit(s) in the grocery bag is: 8.',
    'The number of fruit(s) in the grocery bag is: 9.'
]

def checkout(itemcount, category):
    if category == "fruits":
        if 1 <= itemcount <= 9:
            # List indices start at 0
            print groceryfruits[i-1]


checkout(9, "fruits")

将9个顺序变量合并为1个变量

3 个答案: