Question

这是参考这个问题Grouped result insert into two tables

我有以下架构

create table master (
    master_id serial primary key,
    project_id int,
    category_id int,
    supplier_id int
);
create table detail (
    detail_id int,
    item_id int,
    qty numeric(18,2),
    rate numeric(18,2),
    master_id int references master (master_id)
);
create temporary table temp_detail (
    purchase_order_detail_id integer,
    item_id integer,
    qty numeric(18,2),
    project_id integer,
    category_id integer,
    supplier_id integer,
    rate numeric(18,2)
);

我使用

获得结果

with d as (
    insert into master (project_id, category_id, supplier_id)
    select distinct project_id, category_id, supplier_id
    from temp_detail
    returning *
)
insert into detail (item_id, qty, rate, master_id)
select item_id, qty, rate, master_id
from
    temp_detail td
    inner join
    d on (td.project_id, td.category_id, td.supplier_id) = (d.project_id, d.category_id, d.supplier_id)
;

上面的查询工作正常，但我想使用子查询来增加master_id而不是串行数据类型。请帮忙。

Answer 1

with d as (
    insert into master (master_id, project_id, category_id, supplier_id)
    select row_number() over(), * from(
    select distinct project_id, category_id, supplier_id
    from temp_detail
    )x
    returning *
)
insert into detail (item_id, qty, rate, master_id)
select item_id, qty, rate, master_id
from
    temp_detail td
    inner join
    d on (td.project_id, td.category_id, td.supplier_id) = (d.project_id, d.category_id, d.supplier_id)
;

使用子查询增加id

1 个答案: