Question

我有一张客户表。每个客户都有一个特定的ID。在我的项目（ecommerce website）中，我想在用户成功登录时将其存储在$ _SESSION ['user_id']中。我怎么做？我需要添加什么？这是我的代码：

<?php
// establishing the MySQLi connection
$con = mysqli_connect("localhost","root","","ecommerce");
// checking the user
if(isset($_POST['login'])){
    $email = mysqli_real_escape_string($con,$_POST['c_email']);
    $pass = mysqli_real_escape_string($con,$_POST['pass']);
    $sel_user = "select * from customer where customer_email ='$email' AND customer_pass='$pass'";
    $run_user = mysqli_query($con, $sel_user);
    $check_user = mysqli_num_rows($run_user);
    if($check_user>0){
        $_SESSION['customer_email']=$email;
        echo "<script>window.open('index.php','_self')</script>";
    } else {
        echo "<script>alert('Email or password is not correct, try again!')</script>";
    }
}
?>

Answer 1

首先，如@ chris85所述，请在脚本顶部调用session_start()。

然后，你几乎就在那里。首先，您需要从结果中获取结果对象。

$rows = array();

while ($row = mysql_fetch_assoc($run_user)) {
    $rows[] = $row; // Same as array_push($rows, $row) but has better performance when pushing a single item.
}

然后，假设我们知道只返回了一行：

$customerData = $rows[0];

冷却。现在，设置您想要的任何SESSION变量：

$_SESSION["user_id"] = $customerData["user_id"];
...

此外，正如评论中所述，请不要将用户密码存储为纯文字。你应该哈希并加盐。以下是一篇很好的入门帖：Best way to store password in database

用php获取id

1 个答案: